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Beliebt Geometry >

foki y=(sqrt(x))^4+6(sqrt(x))^2-1

Lösung

foki

y = (x)^{4} + 6 (x)^{2} - 1

Lösung

(- 3, - \frac{39}{4})

Schritte zur Lösung

Rewrite

y = (x)^{4} + 6 (x)^{2} - 1

in the standard form

4 \cdot \frac{1}{4} (y - (- 10)) = (x - (- 3))^{2}

(h, k) = (- 3, - 10), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 3, - 10)

along the y-axis

(- 3, - 10 + p)

= (- 3, - 10 + \frac{1}{4})

Fasse zusammen

(- 3, - \frac{39}{4})

Graph

Beliebte Beispiele

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f oc i (y - 2)^{2} = 16 (x + 1)

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foki x^2-8x+2y+7=0

f oc i x^{2} - 8 x + 2 y + 7 = 0

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