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Beliebt Geometry >

leitkurve y^2-12y-4x+28=0

Lösung

leitkurve

y^{2} - 12 y - 4 x + 28 = 0

Lösung

x = - 3

Schritte zur Lösung

Rewrite

y^{2} - 12 y - 4 x + 28 = 0

in the standard form

4 \cdot 1 \cdot (x - (- 2)) = (y - 6)^{2}

(h, k) = (- 2, 6), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, 6)

x-coordinate

x = - 2 - p

x = - 2 - 1

Fasse zusammen

x = - 3

Graph

Beliebte Beispiele

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