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Beliebt Geometry >

leitkurve (y+1)^2=16(x-3)

Lösung

leitkurve

(y + 1)^{2} = 16 (x - 3)

Lösung

x = - 1

Schritte zur Lösung

Rewrite

(y + 1)^{2} = 16 (x - 3)

in the standard form:

4 \cdot 4 (x - 3) = (y - (- 1))^{2}

(h, k) = (3, - 1), p = 4

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(3, - 1)

x-coordinate

x = 3 - p

x = 3 - 4

Fasse zusammen

x = - 1

Graph

Beliebte Beispiele

leitkurve y=+x^2-2x+5

d i rec t r i x y = + x^{2} - 2 x + 5

leitkurve y=2x^2-7x-3

d i rec t r i x y = 2 x^{2} - 7 x - 3

leitkurve x^2+5x-7

d i rec t r i x x^{2} + 5 x - 7

leitkurve y^2-6y-8x-23=0

d i rec t r i x y^{2} - 6 y - 8 x - 23 = 0

d i rec t r i x t^{2}