cartesian (-3,(5pi)/6)

解答

极坐标转换为笛卡尔坐标

(- 3, \frac{5 π}{6})

(\frac{3 3}{2}, - \frac{3}{2})

求解步骤

x = r \cdot cos (θ)

x = - 3 cos (\frac{5 π}{6})

- 3 cos (\frac{5 π}{6}) = \frac{3 3}{2}

x = \frac{3 3}{2}

y = r \cdot sin (θ)

y = - 3 sin (\frac{5 π}{6})

- 3 sin (\frac{5 π}{6}) = - \frac{3}{2}

y = - \frac{3}{2}

(- 3, \frac{5 π}{6})

的笛卡尔坐标

(\frac{3 3}{2}, - \frac{3}{2})

x = 7

c a r t es ian (9, \frac{5 π}{6})

d er i v a t i v e y = x^{\frac{3}{2}}

f = 3

d er i v a t i v e f (x) = cos (x)