zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的微积分入门 >

tangent y^3+xy^2-5=x+3y^2,\at x=3

解答

切线

y^{3} + x y^{2} - 5 = x + 3 y^{2}, at x = 3

解答

y = - \frac{1}{4} x + \frac{11}{4}

求解步骤

找到切点:

(3, 2)

计算

y^{3} + x y^{2} - 5 = x + 3 y^{2}

的斜率:

\frac{d y}{d x} = \frac{1 - y ^{2}}{y ( - 6 + 2 x + 3 y )}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4}

找到斜率 m=

- \frac{1}{4}

且穿过

(3, 2)

的直线:

y = - \frac{1}{4} x + \frac{11}{4}

y = - \frac{1}{4} x + \frac{11}{4}

流行的例子

s l o p e x = - 7

polar (-sqrt(2),sqrt(2))

p o l a r (- 2, 2)

x^{2} + y^{2} = 9

derivative x^2+y^2=25

d er i v a t i v e x^{2} + y^{2} = 25

p o l a r (0, - 1)