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受欢迎的三角函数 >

tan(2x+10)=1.5

解答

tan (2 x + 1 0^{\circ}) = 1.5

解答

x = \frac{18 0 ^{\circ} n}{2} + \frac{0.98279 \dots}{2} - 5^{\circ}

+1

弧度

x = \frac{0.98279 \dots}{2} - \frac{π}{36} + \frac{π}{2} n

求解步骤

tan (2 x + 1 0^{\circ}) = 1.5

使用反三角函数性质

tan (2 x + 1 0^{\circ}) = 1.5

tan (2 x + 1 0^{\circ}) = 1.5

的通解

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

2 x + 1 0^{\circ} = arctan (1.5) + 18 0^{\circ} n

2 x + 1 0^{\circ} = arctan (1.5) + 18 0^{\circ} n

解

2 x + 1 0^{\circ} = arctan (1.5) + 18 0^{\circ} n : x = \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - 5^{\circ}

2 x + 1 0^{\circ} = arctan (1.5) + 18 0^{\circ} n

将

1 0^{\circ}

到右边

2 x + 1 0^{\circ} = arctan (1.5) + 18 0^{\circ} n

两边减去

1 0^{\circ}

2 x + 1 0^{\circ} - 1 0^{\circ} = arctan (1.5) + 18 0^{\circ} n - 1 0^{\circ}

化简

2 x = arctan (1.5) + 18 0^{\circ} n - 1 0^{\circ}

2 x = arctan (1.5) + 18 0^{\circ} n - 1 0^{\circ}

两边除以

2

2 x = arctan (1.5) + 18 0^{\circ} n - 1 0^{\circ}

两边除以

2

\frac{2 x}{2} = \frac{arctan ( 1.5 )}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{1 0 ^{\circ}}{2}

化简

\frac{2 x}{2} = \frac{arctan ( 1.5 )}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{1 0 ^{\circ}}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{arctan ( 1.5 )}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{1 0 ^{\circ}}{2} : \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - 5^{\circ}

\frac{arctan ( 1.5 )}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{1 0 ^{\circ}}{2}

对同类项分组

= \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - \frac{1 0 ^{\circ}}{2}

\frac{1 0 ^{\circ}}{2} = 5^{\circ}

\frac{1 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{18 \cdot 2}

数字相乘:

18 \cdot 2 = 36

= 5^{\circ}

= \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - 5^{\circ}

x = \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - 5^{\circ}

x = \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - 5^{\circ}

x = \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - 5^{\circ}

x = \frac{18 0 ^{\circ} n}{2} + \frac{arctan ( 1.5 )}{2} - 5^{\circ}

以小数形式表示解

x = \frac{18 0 ^{\circ} n}{2} + \frac{0.98279 \dots}{2} - 5^{\circ}

作图

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