zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

7cos(x)+12=6cos(x)+13

解答

7 cos (x) + 12 = 6 cos (x) + 13

解答

x = 2 πn

+1

度数

x = 0^{\circ} + 36 0^{\circ} n

求解步骤

7 cos (x) + 12 = 6 cos (x) + 13

用替代法求解

7 cos (x) + 12 = 6 cos (x) + 13

令

: cos (x) = u

7 u + 12 = 6 u + 13

7 u + 12 = 6 u + 13 : u = 1

7 u + 12 = 6 u + 13

将

12

到右边

7 u + 12 = 6 u + 13

两边减去

12

7 u + 12 - 12 = 6 u + 13 - 12

化简

7 u = 6 u + 1

7 u = 6 u + 1

将

6 u

para o lado esquerdo

7 u = 6 u + 1

两边减去

6 u

7 u - 6 u = 6 u + 1 - 6 u

化简

u = 1

u = 1

u = cos (x)

代回

cos (x) = 1

cos (x) = 1

cos (x) = 1 : x = 2 πn

cos (x) = 1

cos (x) = 1

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

解

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

合并所有解

x = 2 πn

作图

流行的例子

sin(x/2)+cos(x/2)=sqrt(2)

sin (\frac{x}{2}) + cos (\frac{x}{2}) = 2

2tan(x)-16=0,0<= x< pi/2

2 tan (x) - 16 = 0, 0 \leq x < \frac{π}{2}

4 sec (x) + 6 = - 2

tan (2 x) = \frac{1}{4}

2 tan (x) - 4 = 1