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Popular Trigonometry >

cosh(θ)= 29/8 \land θ<0,sinh(θ)

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Solution

cosh(θ)=829​andθ<0,sinh(θ)

Solution

θ=ln(829−777​​)
+1
Decimal
θ=−1.96140…
Solution steps
cosh(θ)=829​andθ<0
cosh(θ)=829​:θ=ln(829+777​​),θ=ln(829−777​​)
cosh(θ)=829​
Rewrite using trig identities
cosh(θ)=829​
Use the Hyperbolic identity: cosh(x)=2ex+e−x​2eθ+e−θ​=829​
2eθ+e−θ​=829​
2eθ+e−θ​=829​:θ=ln(829+777​​),θ=ln(829−777​​)
2eθ+e−θ​=829​
Apply fraction cross multiply: if ba​=dc​ then a⋅d=b⋅c(eθ+e−θ)⋅8=2⋅29
Simplify(eθ+e−θ)⋅8=58
Apply exponent rules
(eθ+e−θ)⋅8=58
Apply exponent rule: abc=(ab)ce−θ=(eθ)−1(eθ+(eθ)−1)⋅8=58
(eθ+(eθ)−1)⋅8=58
Rewrite the equation with eθ=u(u+(u)−1)⋅8=58
Solve (u+u−1)⋅8=58:u=829+777​​,u=829−777​​
(u+u−1)⋅8=58
Refine(u+u1​)⋅8=58
Simplify (u+u1​)⋅8:8(u+u1​)
(u+u1​)⋅8
Apply the commutative law: (u+u1​)⋅8=8(u+u1​)8(u+u1​)
8(u+u1​)=58
Expand 8(u+u1​):8u+u8​
8(u+u1​)
Apply the distributive law: a(b+c)=ab+aca=8,b=u,c=u1​=8u+8⋅u1​
8⋅u1​=u8​
8⋅u1​
Multiply fractions: a⋅cb​=ca⋅b​=u1⋅8​
Multiply the numbers: 1⋅8=8=u8​
=8u+u8​
8u+u8​=58
Multiply both sides by u
8u+u8​=58
Multiply both sides by u8uu+u8​u=58u
Simplify
8uu+u8​u=58u
Simplify 8uu:8u2
8uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=8u1+1
Add the numbers: 1+1=2=8u2
Simplify u8​u:8
u8​u
Multiply fractions: a⋅cb​=ca⋅b​=u8u​
Cancel the common factor: u=8
8u2+8=58u
8u2+8=58u
8u2+8=58u
Solve 8u2+8=58u:u=829+777​​,u=829−777​​
8u2+8=58u
Move 58uto the left side
8u2+8=58u
Subtract 58u from both sides8u2+8−58u=58u−58u
Simplify8u2+8−58u=0
8u2+8−58u=0
Write in the standard form ax2+bx+c=08u2−58u+8=0
Solve with the quadratic formula
8u2−58u+8=0
Quadratic Equation Formula:
For a=8,b=−58,c=8u1,2​=2⋅8−(−58)±(−58)2−4⋅8⋅8​​
u1,2​=2⋅8−(−58)±(−58)2−4⋅8⋅8​​
(−58)2−4⋅8⋅8​=2777​
(−58)2−4⋅8⋅8​
Apply exponent rule: (−a)n=an,if n is even(−58)2=582=582−4⋅8⋅8​
Multiply the numbers: 4⋅8⋅8=256=582−256​
582=3364=3364−256​
Subtract the numbers: 3364−256=3108=3108​
Prime factorization of 3108:22⋅3⋅7⋅37
3108
3108divides by 23108=1554⋅2=2⋅1554
1554divides by 21554=777⋅2=2⋅2⋅777
777divides by 3777=259⋅3=2⋅2⋅3⋅259
259divides by 7259=37⋅7=2⋅2⋅3⋅7⋅37
2,3,7,37 are all prime numbers, therefore no further factorization is possible=2⋅2⋅3⋅7⋅37
=22⋅3⋅7⋅37
=22⋅3⋅7⋅37​
Apply radical rule: =22​3⋅7⋅37​
Apply radical rule: 22​=2=23⋅7⋅37​
Refine=2777​
u1,2​=2⋅8−(−58)±2777​​
Separate the solutionsu1​=2⋅8−(−58)+2777​​,u2​=2⋅8−(−58)−2777​​
u=2⋅8−(−58)+2777​​:829+777​​
2⋅8−(−58)+2777​​
Apply rule −(−a)=a=2⋅858+2777​​
Multiply the numbers: 2⋅8=16=1658+2777​​
Factor 58+2777​:2(29+777​)
58+2777​
Rewrite as=2⋅29+2777​
Factor out common term 2=2(29+777​)
=162(29+777​)​
Cancel the common factor: 2=829+777​​
u=2⋅8−(−58)−2777​​:829−777​​
2⋅8−(−58)−2777​​
Apply rule −(−a)=a=2⋅858−2777​​
Multiply the numbers: 2⋅8=16=1658−2777​​
Factor 58−2777​:2(29−777​)
58−2777​
Rewrite as=2⋅29−2777​
Factor out common term 2=2(29−777​)
=162(29−777​)​
Cancel the common factor: 2=829−777​​
The solutions to the quadratic equation are:u=829+777​​,u=829−777​​
u=829+777​​,u=829−777​​
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of (u+u−1)8 and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=829+777​​,u=829−777​​
u=829+777​​,u=829−777​​
Substitute back u=eθ,solve for θ
Solve eθ=829+777​​:θ=ln(829+777​​)
eθ=829+777​​
Apply exponent rules
eθ=829+777​​
If f(x)=g(x), then ln(f(x))=ln(g(x))ln(eθ)=ln(829+777​​)
Apply log rule: ln(ea)=aln(eθ)=θθ=ln(829+777​​)
θ=ln(829+777​​)
Solve eθ=829−777​​:θ=ln(829−777​​)
eθ=829−777​​
Apply exponent rules
eθ=829−777​​
If f(x)=g(x), then ln(f(x))=ln(g(x))ln(eθ)=ln(829−777​​)
Apply log rule: ln(ea)=aln(eθ)=θθ=ln(829−777​​)
θ=ln(829−777​​)
θ=ln(829+777​​),θ=ln(829−777​​)
θ=ln(829+777​​),θ=ln(829−777​​)
Combine the intervals(θ=ln(829−777​​)orθ=ln(829+777​​))andθ<0
Merge Overlapping Intervals
θ=ln(829−777​​)orθ=ln(829+777​​)andθ<0
The intersection of two intervals is the set of numbers which are in both intervals
θ=ln(829−777​​)orθ=ln(829+777​​)andθ<0
θ=ln(829−777​​)
θ=ln(829−777​​)

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