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受欢迎的三角函数 >

sqrt(2)cos(-pi/4)+pi/4

解答

2 cos (- \frac{π}{4}) + \frac{π}{4}

解答

1 + \frac{π}{4}

+1

十进制

1.78539 \dots

求解步骤

2 cos (- \frac{π}{4}) + \frac{π}{4}

使用三角恒等式改写:

cos (- \frac{π}{4}) = \frac{2}{2}

cos (- \frac{π}{4})

利用以下特性:

cos (- x) = cos (x)

cos (- \frac{π}{4}) = cos (\frac{π}{4})

= cos (\frac{π}{4})

使用以下普通恒等式:

cos (\frac{π}{4}) = \frac{2}{2}

cos (\frac{π}{4})

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

= \frac{2}{2}

= 2 \frac{2}{2} + \frac{π}{4}

化简

2 \frac{2}{2} + \frac{π}{4} : 1 + \frac{π}{4}

2 \frac{2}{2} + \frac{π}{4}

2 \frac{2}{2} = 1

2 \frac{2}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 2}{2}

22 = 2

22

使用根式运算法则:

a a = a

22 = 2

= 2

= \frac{2}{2}

使用法则

\frac{a}{a} = 1

= 1

= 1 + \frac{π}{4}

= 1 + \frac{π}{4}

流行的例子

cos((3pi)/5)cos((7pi}{30})-sin((3pi)/5)sin(\frac{7pi)/(30))

cos (\frac{3 π}{5}) cos (\frac{7 π}{30}) - sin (\frac{3 π}{5}) sin (\frac{7 π}{30})

sec (\frac{π}{16})

(4.5)/(cos(54))

\frac{4.5}{cos ( 5 4 ^{\circ} )}

6.377563396*(cos(29.462486))

6.377563396 \cdot (cos (29.46248 6^{\circ}))

(sec(0))/(tan(0))

\frac{sec ( 0 )}{tan ( 0 )}