(sin^2(-pi))/(sec^2(-pi)-1)

解答

\frac{sin ^{2} ( - π )}{sec ^{2} ( - π ) - 1}

未定义

求解步骤

\frac{sin ^{2} ( - π )}{sec ^{2} ( - π ) - 1}

sec^{2} (- π) - 1 = 0

= \frac{sin ^{2} ( - π )}{0}

\frac{x}{0}

不在定义域

= 未定义

tanh (\frac{π}{4})

ln tan (\frac{π}{3}) + sec (\frac{π}{3})

sin (7.6)

3 \cdot sin (\frac{π}{4})

arctan (\frac{3.73}{9.8} + 0.6)