(csc(45))(sec(45))

Solución

(csc (4 5^{\circ})) (sec (4 5^{\circ}))

2

Pasos de solución

(csc (4 5^{\circ})) (sec (4 5^{\circ}))

= csc (4 5^{\circ}) sec (4 5^{\circ})

Utilizar la siguiente identidad trivial:

csc (4 5^{\circ}) = 2

csc (4 5^{\circ})

csc (x)

tabla de valores periódicos con

36 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

= 2

Utilizar la siguiente identidad trivial:

sec (4 5^{\circ}) = 2

sec (4 5^{\circ})

sec (x)

tabla de valores periódicos con

36 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= 2

= 22

Simplificar

22 : 2

22

Aplicar las leyes de los exponentes:

a a = a

22 = 2

= 2

= 2