zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

cos(180-x)=sin(-300)

解答

cos (18 0^{\circ} - x) = sin (- 30 0^{\circ})

解答

x = 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}, x = 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

+1

弧度

x = π - \frac{π}{6} - 2 πn, x = π - \frac{11 π}{6} - 2 πn

求解步骤

cos (18 0^{\circ} - x) = sin (- 30 0^{\circ})

sin (- 30 0^{\circ}) = \frac{3}{2}

sin (- 30 0^{\circ})

利用以下特性:

sin (- x) = - sin (x)

sin (- 30 0^{\circ}) = - sin (30 0^{\circ})

= - sin (30 0^{\circ})

使用三角恒等式改写:

sin (30 0^{\circ}) = - \frac{3}{2}

sin (30 0^{\circ})

使用三角恒等式改写:

sin (18 0^{\circ}) cos (12 0^{\circ}) + cos (18 0^{\circ}) sin (12 0^{\circ})

sin (30 0^{\circ})

将

sin (30 0^{\circ})

写为

sin (18 0^{\circ} + 12 0^{\circ})

= sin (18 0^{\circ} + 12 0^{\circ})

使用角和恒等式:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

= sin (18 0^{\circ}) cos (12 0^{\circ}) + cos (18 0^{\circ}) sin (12 0^{\circ})

= sin (18 0^{\circ}) cos (12 0^{\circ}) + cos (18 0^{\circ}) sin (12 0^{\circ})

使用以下普通恒等式:

sin (18 0^{\circ}) = 0

sin (18 0^{\circ})

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

使用以下普通恒等式:

cos (12 0^{\circ}) = - \frac{1}{2}

cos (12 0^{\circ})

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{1}{2}

使用以下普通恒等式:

cos (18 0^{\circ}) = (- 1)

cos (18 0^{\circ})

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

使用以下普通恒等式:

sin (12 0^{\circ}) = \frac{3}{2}

sin (12 0^{\circ})

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= 0 \cdot (- \frac{1}{2}) + (- 1) \frac{3}{2}

化简

= - \frac{3}{2}

= - (- \frac{3}{2})

化简

= \frac{3}{2}

cos (18 0^{\circ} - x) = \frac{3}{2}

cos (18 0^{\circ} - x) = \frac{3}{2}

的通解

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

18 0^{\circ} - x = 3 0^{\circ} + 36 0^{\circ} n, 18 0^{\circ} - x = 33 0^{\circ} + 36 0^{\circ} n

18 0^{\circ} - x = 3 0^{\circ} + 36 0^{\circ} n, 18 0^{\circ} - x = 33 0^{\circ} + 36 0^{\circ} n

解

18 0^{\circ} - x = 3 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}

18 0^{\circ} - x = 3 0^{\circ} + 36 0^{\circ} n

将

18 0^{\circ}

到右边

18 0^{\circ} - x = 3 0^{\circ} + 36 0^{\circ} n

两边减去

18 0^{\circ}

18 0^{\circ} - x - 18 0^{\circ} = 3 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

化简

- x = 3 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

- x = 3 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

两边除以

- 1

- x = 3 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

两边除以

- 1

\frac{- x}{- 1} = \frac{3 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1}

化简

\frac{- x}{- 1} = \frac{3 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1}

化简

\frac{- x}{- 1} : x

\frac{- x}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{3 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1} : 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}

\frac{3 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1}

对同类项分组

= - \frac{18 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} + \frac{3 0 ^{\circ}}{- 1}

\frac{18 0 ^{\circ}}{- 1} = - 18 0^{\circ}

\frac{18 0 ^{\circ}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - 18 0^{\circ}

使用法则

\frac{a}{1} = a

= - 18 0^{\circ}

\frac{36 0 ^{\circ} n}{- 1} = - 36 0^{\circ} n

\frac{36 0 ^{\circ} n}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{36 0 ^{\circ} n}{1}

使用法则

\frac{a}{1} = a

= - 36 0^{\circ} n

= - (- 18 0^{\circ}) - 36 0^{\circ} n + \frac{3 0 ^{\circ}}{- 1}

使用法则

- (- a) = a

= 18 0^{\circ} - 36 0^{\circ} n + \frac{3 0 ^{\circ}}{- 1}

\frac{3 0 ^{\circ}}{- 1} = - 3 0^{\circ}

\frac{3 0 ^{\circ}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{3 0 ^{\circ}}{1}

使用分式法则:

\frac{a}{1} = a

\frac{3 0 ^{\circ}}{1} = 3 0^{\circ}

= - 3 0^{\circ}

= 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}

x = 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}

x = 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}

x = 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}

解

18 0^{\circ} - x = 33 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

18 0^{\circ} - x = 33 0^{\circ} + 36 0^{\circ} n

将

18 0^{\circ}

到右边

18 0^{\circ} - x = 33 0^{\circ} + 36 0^{\circ} n

两边减去

18 0^{\circ}

18 0^{\circ} - x - 18 0^{\circ} = 33 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

化简

- x = 33 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

- x = 33 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

两边除以

- 1

- x = 33 0^{\circ} + 36 0^{\circ} n - 18 0^{\circ}

两边除以

- 1

\frac{- x}{- 1} = \frac{33 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1}

化简

\frac{- x}{- 1} = \frac{33 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1}

化简

\frac{- x}{- 1} : x

\frac{- x}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{33 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1} : 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

\frac{33 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} - \frac{18 0 ^{\circ}}{- 1}

对同类项分组

= - \frac{18 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} + \frac{33 0 ^{\circ}}{- 1}

\frac{18 0 ^{\circ}}{- 1} = - 18 0^{\circ}

\frac{18 0 ^{\circ}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - 18 0^{\circ}

使用法则

\frac{a}{1} = a

= - 18 0^{\circ}

\frac{36 0 ^{\circ} n}{- 1} = - 36 0^{\circ} n

\frac{36 0 ^{\circ} n}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{36 0 ^{\circ} n}{1}

使用法则

\frac{a}{1} = a

= - 36 0^{\circ} n

= - (- 18 0^{\circ}) - 36 0^{\circ} n + \frac{33 0 ^{\circ}}{- 1}

使用法则

- (- a) = a

= 18 0^{\circ} - 36 0^{\circ} n + \frac{33 0 ^{\circ}}{- 1}

\frac{33 0 ^{\circ}}{- 1} = - 33 0^{\circ}

\frac{33 0 ^{\circ}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{33 0 ^{\circ}}{1}

使用分式法则:

\frac{a}{1} = a

\frac{33 0 ^{\circ}}{1} = 33 0^{\circ}

= - 33 0^{\circ}

= 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

x = 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

x = 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

x = 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

x = 18 0^{\circ} - 36 0^{\circ} n - 3 0^{\circ}, x = 18 0^{\circ} - 36 0^{\circ} n - 33 0^{\circ}

作图

流行的例子

cos (θ) = 0.417

tan (x) = 2.7475

2+3cot^2(θ)-3csc(θ)=5

2 + 3 cot^{2} (θ) - 3 csc (θ) = 5

2sin(6x)+2sin(2x)=0

2 sin (6 x) + 2 sin (2 x) = 0

tan^2(2x)-1=sec(2x)

tan^{2} (2 x) - 1 = sec (2 x)