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受欢迎的三角函数 >

(2sin(x)-1)(cos(x)-sqrt(2))=0

解答

(2 sin (x) - 1) (cos (x) - 2) = 0

解答

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

+1

度数

x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

求解步骤

(2 sin (x) - 1) (cos (x) - 2) = 0

分别求解每个部分

2 sin (x) - 1 = 0 or cos (x) - 2 = 0

2 sin (x) - 1 = 0 : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

2 sin (x) - 1 = 0

将

1

到右边

2 sin (x) - 1 = 0

两边加上

1

2 sin (x) - 1 + 1 = 0 + 1

化简

2 sin (x) = 1

2 sin (x) = 1

两边除以

2

2 sin (x) = 1

两边除以

2

\frac{2 sin ( x )}{2} = \frac{1}{2}

化简

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2}

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

cos (x) - 2 = 0 :

无解

cos (x) - 2 = 0

将

2

到右边

cos (x) - 2 = 0

两边加上

2

cos (x) - 2 + 2 = 0 + 2

化简

cos (x) = 2

cos (x) = 2

- 1 \leq cos (x) \leq 1

无解

合并所有解

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

作图

流行的例子

sin (a) = \frac{9}{41}

sin (x) = \frac{10}{300}

cos(216)=cos^2(a)-sin^2(a)

cos (21 6^{\circ}) = cos^{2} (a) - sin^{2} (a)

csc(-x)-1=cot^2(x)

csc (- x) - 1 = cot^{2} (x)

sin(x)=-cos^2(x)

sin (x) = - cos^{2} (x)