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人気のある三角関数 >

tan(45+x/3)=0.58

解

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

解

x = 3 \cdot 0.52558 \dots + 54 0^{\circ} n - 13 5^{\circ}

+1

ラジアン

x = 3 \cdot 0.52558 \dots - \frac{3 π}{4} + 3 πn

解答ステップ

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

三角関数の逆数プロパティを適用する

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

以下の一般解

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

解く

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n : x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

4 5^{\circ}

を右側に移動します

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

両辺から

4 5^{\circ}

を引く

4 5^{\circ} + \frac{x}{3} - 4 5^{\circ} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

簡素化

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

以下で両辺を乗じる:

3

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

以下で両辺を乗じる:

3

\frac{3 x}{3} = 3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

簡素化

\frac{3 x}{3} = 3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

簡素化

\frac{3 x}{3} : x

\frac{3 x}{3}

数を割る:

\frac{3}{3} = 1

= x

簡素化

3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ} : 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

乗じる

3 \cdot 4 5^{\circ} : 13 5^{\circ}

3 \cdot 4 5^{\circ}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 13 5^{\circ}

= 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

10進法形式で解を証明する

x = 3 \cdot 0.52558 \dots + 54 0^{\circ} n - 13 5^{\circ}

グラフ

人気の例

r = a (1 + sin (x))

tan(Θ)=1.4,180<,Θ<270

tan (Θ) = 1.4, 18 0^{\circ} <, Θ < 27 0^{\circ}

(1+4cos(θ))^2=(sqrt(3)sin(θ))

(1 + 4 cos (θ))^{2} = (3 sin (θ))

sin(θ)-(cos(θ))/5 =0.6377

sin (θ) - \frac{cos ( θ )}{5} = 0.6377

sin(4x)=cos(4x)

sin (4 x) = cos (4 x)