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受欢迎的三角函数 >

27^2=56^2+35^2-(25635*cos(x))

解答

2 7^{2} = 5 6^{2} + 3 5^{2} - (2 \cdot 56 \cdot 35 \cdot cos (x))

解答

x = 0.38571 \dots + 2 πn, x = 2 π - 0.38571 \dots + 2 πn

+1

度数

x = 22.09969 \dots^{\circ} + 36 0^{\circ} n, x = 337.90030 \dots^{\circ} + 36 0^{\circ} n

求解步骤

2 7^{2} = 5 6^{2} + 3 5^{2} - (2 \cdot 56 \cdot 35 cos (x))

交换两边

5 6^{2} + 3 5^{2} - 2 \cdot 56 \cdot 35 cos (x) = 2 7^{2}

数字相乘:

2 \cdot 56 \cdot 35 = 3920

5 6^{2} + 3 5^{2} - 3920 cos (x) = 2 7^{2}

5 6^{2} = 3136

3136 + 3 5^{2} - 3920 cos (x) = 2 7^{2}

3 5^{2} = 1225

3136 + 1225 - 3920 cos (x) = 2 7^{2}

数字相加:

3136 + 1225 = 4361

- 3920 cos (x) + 4361 = 2 7^{2}

2 7^{2} = 729

- 3920 cos (x) + 4361 = 729

将

4361

到右边

- 3920 cos (x) + 4361 = 729

两边减去

4361

- 3920 cos (x) + 4361 - 4361 = 729 - 4361

化简

- 3920 cos (x) = - 3632

- 3920 cos (x) = - 3632

两边除以

- 3920

- 3920 cos (x) = - 3632

两边除以

- 3920

\frac{- 3920 cos ( x )}{- 3920} = \frac{- 3632}{- 3920}

化简

\frac{- 3920 cos ( x )}{- 3920} = \frac{- 3632}{- 3920}

化简

\frac{- 3920 cos ( x )}{- 3920} : cos (x)

\frac{- 3920 cos ( x )}{- 3920}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3920 cos ( x )}{3920}

数字相除:

\frac{3920}{3920} = 1

= cos (x)

化简

\frac{- 3632}{- 3920} : \frac{227}{245}

\frac{- 3632}{- 3920}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3632}{3920}

约分:

16

= \frac{227}{245}

cos (x) = \frac{227}{245}

cos (x) = \frac{227}{245}

cos (x) = \frac{227}{245}

使用反三角函数性质

cos (x) = \frac{227}{245}

cos (x) = \frac{227}{245}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{227}{245}) + 2 πn, x = 2 π - arccos (\frac{227}{245}) + 2 πn

x = arccos (\frac{227}{245}) + 2 πn, x = 2 π - arccos (\frac{227}{245}) + 2 πn

以小数形式表示解

x = 0.38571 \dots + 2 πn, x = 2 π - 0.38571 \dots + 2 πn

作图

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