cos(θ)= 9/15

Lösung

cos (θ) = \frac{9}{15}

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

Grad

θ = 53.13010 \dots^{\circ} + 36 0^{\circ} n, θ = 306.86989 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{9}{15}

Streiche die gemeinsamen Faktoren:

3

cos (θ) = \frac{3}{5}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{3}{5}

Allgemeine Lösung für

cos (θ) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

tan (t) = - \frac{5}{12}

1 - 3 cos (x) - cos (2 x) = 0

cot (θ) = \frac{12}{5}, tan (θ)

sin (a) = cos (\frac{π}{2} - θ)

tan (θ) + sec (θ) = 2 cos (θ)