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受欢迎的三角函数 >

(-5cot(x))/2+7/3 =-1/6

解答

\frac{- 5 cot ( x )}{2} + \frac{7}{3} = - \frac{1}{6}

解答

x = \frac{π}{4} + πn

+1

度数

x = 4 5^{\circ} + 18 0^{\circ} n

求解步骤

\frac{- 5 cot ( x )}{2} + \frac{7}{3} = - \frac{1}{6}

将

\frac{7}{3}

到右边

\frac{- 5 cot ( x )}{2} + \frac{7}{3} = - \frac{1}{6}

两边减去

\frac{7}{3}

\frac{- 5 cot ( x )}{2} + \frac{7}{3} - \frac{7}{3} = - \frac{1}{6} - \frac{7}{3}

化简

\frac{- 5 cot ( x )}{2} + \frac{7}{3} - \frac{7}{3} = - \frac{1}{6} - \frac{7}{3}

化简

\frac{- 5 cot ( x )}{2} + \frac{7}{3} - \frac{7}{3} : \frac{- 5 cot ( x )}{2}

\frac{- 5 cot ( x )}{2} + \frac{7}{3} - \frac{7}{3}

同类项相加:

\frac{7}{3} - \frac{7}{3} = 0

= \frac{- 5 cot ( x )}{2}

化简

- \frac{1}{6} - \frac{7}{3} : - \frac{5}{2}

- \frac{1}{6} - \frac{7}{3}

6, 3

的最小公倍数:

6

6, 3

最小公倍数 (LCM)

6

质因数分解:

2 \cdot 3

6

6

除以

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

都是质数，因此无法进一步因数分解

= 2 \cdot 3

3

质因数分解:

3

3

3

是质数，因此无法因数分解

= 3

将每个因子乘以它在

6

或

3

中出现的最多次数

= 2 \cdot 3

数字相乘:

2 \cdot 3 = 6

= 6

根据最小公倍数调整分式

将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值

6

对于

\frac{7}{3} :

将分母和分子乘以

2

\frac{7}{3} = \frac{7 \cdot 2}{3 \cdot 2} = \frac{14}{6}

= - \frac{1}{6} - \frac{14}{6}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 - 14}{6}

数字相减:

- 1 - 14 = - 15

= \frac{- 15}{6}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{15}{6}

约分:

3

= - \frac{5}{2}

\frac{- 5 cot ( x )}{2} = - \frac{5}{2}

\frac{- 5 cot ( x )}{2} = - \frac{5}{2}

\frac{- 5 cot ( x )}{2} = - \frac{5}{2}

在两边乘以

2

\frac{- 5 cot ( x )}{2} = - \frac{5}{2}

在两边乘以

2

\frac{2 ( - 5 cot ( x ) )}{2} = 2 (- \frac{5}{2})

化简

\frac{2 ( - 5 cot ( x ) )}{2} = 2 (- \frac{5}{2})

化简

\frac{2 ( - 5 cot ( x ) )}{2} : - 5 cot (x)

\frac{2 ( - 5 cot ( x ) )}{2}

去除括号:

(- a) = - a

= \frac{- 2 \cdot 5 cot ( x )}{2}

数字相乘:

2 \cdot 5 = 10

= \frac{- 10 cot ( x )}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{10 cot ( x )}{2}

数字相除:

\frac{10}{2} = 5

= - 5 cot (x)

化简

2 (- \frac{5}{2}) : - 5

2 (- \frac{5}{2})

去除括号:

(- a) = - a

= - 2 \cdot \frac{5}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{5 \cdot 2}{2}

约分:

2

= - 5

- 5 cot (x) = - 5

- 5 cot (x) = - 5

- 5 cot (x) = - 5

两边除以

- 5

- 5 cot (x) = - 5

两边除以

- 5

\frac{- 5 cot ( x )}{- 5} = \frac{- 5}{- 5}

化简

cot (x) = 1

cot (x) = 1

cot (x) = 1

的通解

cot (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

作图

流行的例子

8.59tan^2(θ)-24tan(θ)+15.29=0

8.59 tan^{2} (θ) - 24 tan (θ) + 15.29 = 0

(csc(x))=-csc(x)cot(x)

(csc (x)) = - csc (x) cot (x)

cot (x) = - \frac{4}{3}

(cos^2(x))/(sin^2(x))=1

\frac{cos ^{2} ( x )}{sin ^{2} ( x )} = 1

solvefor x,f=(cos(2x))/(cos(x)-sin(x))

so l v e f or x, f = \frac{cos ( 2 x )}{cos ( x ) - sin ( x )}