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Popular Trigonometria >

sin^3(x)+sin(x)=2sin^{22}(x)

Solução

sin^{3} (x) + sin (x) = 2 sin^{22} (x)

Solução

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

Graus

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 9 0^{\circ} + 36 0^{\circ} n

Passos da solução

sin^{3} (x) + sin (x) = 2 sin^{22} (x)

Usando o método de substituição

sin^{3} (x) + sin (x) = 2 sin^{22} (x)

Sea:

sin (x) = u

u^{3} + u = 2 u^{22}

u^{3} + u = 2 u^{22} : u = 0, u = 1

u^{3} + u = 2 u^{22}

Trocar lados

2 u^{22} = u^{3} + u

Mova

u

para o lado esquerdo

2 u^{22} = u^{3} + u

Subtrair

u

de ambos os lados

2 u^{22} - u = u^{3} + u - u

Simplificar

2 u^{22} - u = u^{3}

2 u^{22} - u = u^{3}

Mova

u^{3}

para o lado esquerdo

2 u^{22} - u = u^{3}

Subtrair

u^{3}

de ambos os lados

2 u^{22} - u - u^{3} = u^{3} - u^{3}

Simplificar

2 u^{22} - u - u^{3} = 0

2 u^{22} - u - u^{3} = 0

Fatorar

2 u^{22} - u - u^{3} : u (u - 1) (2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1)

2 u^{22} - u - u^{3}

Fatorar o termo comum

u : u (2 u^{21} - u^{2} - 1)

2 u^{22} - u^{3} - u

Aplicar as propriedades dos expoentes:

a^{b + c} = a^{b} a^{c}

u^{3} = u^{2} u

= 2 u^{21} u - u^{2} u - u

Fatorar o termo comum

u

= u (2 u^{21} - u^{2} - 1)

= u (2 u^{21} - u^{2} - 1)

Fatorar

2 u^{21} - u^{2} - 1 : (u - 1) (2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1)

2 u^{21} - u^{2} - 1

Utilizar o teorema das raízes racionais

a_{0} = 1, a_{n} = 2

Os divisores de

a_{0} : 1,

Os divisores de

a_{n} : 1, 2

Portanto, verificar os seguintes números racionais:

\pm \frac{1}{1 , 2}

\frac{1}{1}

é a raiz da expressão, portanto, fatorar

u - 1

= (u - 1) \frac{2 u ^{21} - u ^{2} - 1}{u - 1}

\frac{2 u ^{21} - u ^{2} - 1}{u - 1} = 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1

\frac{2 u ^{21} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{21} - u ^{2} - 1}{u - 1} : \frac{2 u ^{21} - u ^{2} - 1}{u - 1} = 2 u^{20} + \frac{2 u ^{20} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{21} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{21}}{u} = 2 u^{20}

Quociente = 2 u^{20}

Multiplicar

u - 1

por

2 u^{20} : 2 u^{21} - 2 u^{20}

Subtrair

2 u^{21} - 2 u^{20}

2 u^{21} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{20} - u^{2} - 1

Portanto

\frac{2 u ^{21} - u ^{2} - 1}{u - 1} = 2 u^{20} + \frac{2 u ^{20} - u ^{2} - 1}{u - 1}

= 2 u^{20} + \frac{2 u ^{20} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{20} - u ^{2} - 1}{u - 1} : \frac{2 u ^{20} - u ^{2} - 1}{u - 1} = 2 u^{19} + \frac{2 u ^{19} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{20} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{20}}{u} = 2 u^{19}

Quociente = 2 u^{19}

Multiplicar

u - 1

por

2 u^{19} : 2 u^{20} - 2 u^{19}

Subtrair

2 u^{20} - 2 u^{19}

2 u^{20} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{19} - u^{2} - 1

Portanto

\frac{2 u ^{20} - u ^{2} - 1}{u - 1} = 2 u^{19} + \frac{2 u ^{19} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + \frac{2 u ^{19} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{19} - u ^{2} - 1}{u - 1} : \frac{2 u ^{19} - u ^{2} - 1}{u - 1} = 2 u^{18} + \frac{2 u ^{18} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{19} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{19}}{u} = 2 u^{18}

Quociente = 2 u^{18}

Multiplicar

u - 1

por

2 u^{18} : 2 u^{19} - 2 u^{18}

Subtrair

2 u^{19} - 2 u^{18}

2 u^{19} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{18} - u^{2} - 1

Portanto

\frac{2 u ^{19} - u ^{2} - 1}{u - 1} = 2 u^{18} + \frac{2 u ^{18} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + \frac{2 u ^{18} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{18} - u ^{2} - 1}{u - 1} : \frac{2 u ^{18} - u ^{2} - 1}{u - 1} = 2 u^{17} + \frac{2 u ^{17} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{18} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{18}}{u} = 2 u^{17}

Quociente = 2 u^{17}

Multiplicar

u - 1

por

2 u^{17} : 2 u^{18} - 2 u^{17}

Subtrair

2 u^{18} - 2 u^{17}

2 u^{18} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{17} - u^{2} - 1

Portanto

\frac{2 u ^{18} - u ^{2} - 1}{u - 1} = 2 u^{17} + \frac{2 u ^{17} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + \frac{2 u ^{17} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{17} - u ^{2} - 1}{u - 1} : \frac{2 u ^{17} - u ^{2} - 1}{u - 1} = 2 u^{16} + \frac{2 u ^{16} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{17} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{17}}{u} = 2 u^{16}

Quociente = 2 u^{16}

Multiplicar

u - 1

por

2 u^{16} : 2 u^{17} - 2 u^{16}

Subtrair

2 u^{17} - 2 u^{16}

2 u^{17} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{16} - u^{2} - 1

Portanto

\frac{2 u ^{17} - u ^{2} - 1}{u - 1} = 2 u^{16} + \frac{2 u ^{16} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + \frac{2 u ^{16} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{16} - u ^{2} - 1}{u - 1} : \frac{2 u ^{16} - u ^{2} - 1}{u - 1} = 2 u^{15} + \frac{2 u ^{15} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{16} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{16}}{u} = 2 u^{15}

Quociente = 2 u^{15}

Multiplicar

u - 1

por

2 u^{15} : 2 u^{16} - 2 u^{15}

Subtrair

2 u^{16} - 2 u^{15}

2 u^{16} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{15} - u^{2} - 1

Portanto

\frac{2 u ^{16} - u ^{2} - 1}{u - 1} = 2 u^{15} + \frac{2 u ^{15} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + \frac{2 u ^{15} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{15} - u ^{2} - 1}{u - 1} : \frac{2 u ^{15} - u ^{2} - 1}{u - 1} = 2 u^{14} + \frac{2 u ^{14} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{15} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{15}}{u} = 2 u^{14}

Quociente = 2 u^{14}

Multiplicar

u - 1

por

2 u^{14} : 2 u^{15} - 2 u^{14}

Subtrair

2 u^{15} - 2 u^{14}

2 u^{15} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{14} - u^{2} - 1

Portanto

\frac{2 u ^{15} - u ^{2} - 1}{u - 1} = 2 u^{14} + \frac{2 u ^{14} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + \frac{2 u ^{14} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{14} - u ^{2} - 1}{u - 1} : \frac{2 u ^{14} - u ^{2} - 1}{u - 1} = 2 u^{13} + \frac{2 u ^{13} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{14} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{14}}{u} = 2 u^{13}

Quociente = 2 u^{13}

Multiplicar

u - 1

por

2 u^{13} : 2 u^{14} - 2 u^{13}

Subtrair

2 u^{14} - 2 u^{13}

2 u^{14} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{13} - u^{2} - 1

Portanto

\frac{2 u ^{14} - u ^{2} - 1}{u - 1} = 2 u^{13} + \frac{2 u ^{13} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + \frac{2 u ^{13} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{13} - u ^{2} - 1}{u - 1} : \frac{2 u ^{13} - u ^{2} - 1}{u - 1} = 2 u^{12} + \frac{2 u ^{12} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{13} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{13}}{u} = 2 u^{12}

Quociente = 2 u^{12}

Multiplicar

u - 1

por

2 u^{12} : 2 u^{13} - 2 u^{12}

Subtrair

2 u^{13} - 2 u^{12}

2 u^{13} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{12} - u^{2} - 1

Portanto

\frac{2 u ^{13} - u ^{2} - 1}{u - 1} = 2 u^{12} + \frac{2 u ^{12} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + \frac{2 u ^{12} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{12} - u ^{2} - 1}{u - 1} : \frac{2 u ^{12} - u ^{2} - 1}{u - 1} = 2 u^{11} + \frac{2 u ^{11} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{12} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{12}}{u} = 2 u^{11}

Quociente = 2 u^{11}

Multiplicar

u - 1

por

2 u^{11} : 2 u^{12} - 2 u^{11}

Subtrair

2 u^{12} - 2 u^{11}

2 u^{12} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{11} - u^{2} - 1

Portanto

\frac{2 u ^{12} - u ^{2} - 1}{u - 1} = 2 u^{11} + \frac{2 u ^{11} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + \frac{2 u ^{11} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{11} - u ^{2} - 1}{u - 1} : \frac{2 u ^{11} - u ^{2} - 1}{u - 1} = 2 u^{10} + \frac{2 u ^{10} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{11} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{11}}{u} = 2 u^{10}

Quociente = 2 u^{10}

Multiplicar

u - 1

por

2 u^{10} : 2 u^{11} - 2 u^{10}

Subtrair

2 u^{11} - 2 u^{10}

2 u^{11} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{10} - u^{2} - 1

Portanto

\frac{2 u ^{11} - u ^{2} - 1}{u - 1} = 2 u^{10} + \frac{2 u ^{10} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + \frac{2 u ^{10} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{10} - u ^{2} - 1}{u - 1} : \frac{2 u ^{10} - u ^{2} - 1}{u - 1} = 2 u^{9} + \frac{2 u ^{9} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{10} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{10}}{u} = 2 u^{9}

Quociente = 2 u^{9}

Multiplicar

u - 1

por

2 u^{9} : 2 u^{10} - 2 u^{9}

Subtrair

2 u^{10} - 2 u^{9}

2 u^{10} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{9} - u^{2} - 1

Portanto

\frac{2 u ^{10} - u ^{2} - 1}{u - 1} = 2 u^{9} + \frac{2 u ^{9} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + \frac{2 u ^{9} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{9} - u ^{2} - 1}{u - 1} : \frac{2 u ^{9} - u ^{2} - 1}{u - 1} = 2 u^{8} + \frac{2 u ^{8} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{9} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{9}}{u} = 2 u^{8}

Quociente = 2 u^{8}

Multiplicar

u - 1

por

2 u^{8} : 2 u^{9} - 2 u^{8}

Subtrair

2 u^{9} - 2 u^{8}

2 u^{9} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{8} - u^{2} - 1

Portanto

\frac{2 u ^{9} - u ^{2} - 1}{u - 1} = 2 u^{8} + \frac{2 u ^{8} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + \frac{2 u ^{8} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{8} - u ^{2} - 1}{u - 1} : \frac{2 u ^{8} - u ^{2} - 1}{u - 1} = 2 u^{7} + \frac{2 u ^{7} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{8} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{8}}{u} = 2 u^{7}

Quociente = 2 u^{7}

Multiplicar

u - 1

por

2 u^{7} : 2 u^{8} - 2 u^{7}

Subtrair

2 u^{8} - 2 u^{7}

2 u^{8} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{7} - u^{2} - 1

Portanto

\frac{2 u ^{8} - u ^{2} - 1}{u - 1} = 2 u^{7} + \frac{2 u ^{7} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + \frac{2 u ^{7} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{7} - u ^{2} - 1}{u - 1} : \frac{2 u ^{7} - u ^{2} - 1}{u - 1} = 2 u^{6} + \frac{2 u ^{6} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{7} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{7}}{u} = 2 u^{6}

Quociente = 2 u^{6}

Multiplicar

u - 1

por

2 u^{6} : 2 u^{7} - 2 u^{6}

Subtrair

2 u^{7} - 2 u^{6}

2 u^{7} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{6} - u^{2} - 1

Portanto

\frac{2 u ^{7} - u ^{2} - 1}{u - 1} = 2 u^{6} + \frac{2 u ^{6} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + \frac{2 u ^{6} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{6} - u ^{2} - 1}{u - 1} : \frac{2 u ^{6} - u ^{2} - 1}{u - 1} = 2 u^{5} + \frac{2 u ^{5} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{6} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{6}}{u} = 2 u^{5}

Quociente = 2 u^{5}

Multiplicar

u - 1

por

2 u^{5} : 2 u^{6} - 2 u^{5}

Subtrair

2 u^{6} - 2 u^{5}

2 u^{6} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{5} - u^{2} - 1

Portanto

\frac{2 u ^{6} - u ^{2} - 1}{u - 1} = 2 u^{5} + \frac{2 u ^{5} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + \frac{2 u ^{5} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{5} - u ^{2} - 1}{u - 1} : \frac{2 u ^{5} - u ^{2} - 1}{u - 1} = 2 u^{4} + \frac{2 u ^{4} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{5} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{5}}{u} = 2 u^{4}

Quociente = 2 u^{4}

Multiplicar

u - 1

por

2 u^{4} : 2 u^{5} - 2 u^{4}

Subtrair

2 u^{5} - 2 u^{4}

2 u^{5} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{4} - u^{2} - 1

Portanto

\frac{2 u ^{5} - u ^{2} - 1}{u - 1} = 2 u^{4} + \frac{2 u ^{4} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + \frac{2 u ^{4} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{4} - u ^{2} - 1}{u - 1} : \frac{2 u ^{4} - u ^{2} - 1}{u - 1} = 2 u^{3} + \frac{2 u ^{3} - u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{4} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{4}}{u} = 2 u^{3}

Quociente = 2 u^{3}

Multiplicar

u - 1

por

2 u^{3} : 2 u^{4} - 2 u^{3}

Subtrair

2 u^{4} - 2 u^{3}

2 u^{4} - u^{2} - 1

para obter um novo resto

Resto = 2 u^{3} - u^{2} - 1

Portanto

\frac{2 u ^{4} - u ^{2} - 1}{u - 1} = 2 u^{3} + \frac{2 u ^{3} - u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + \frac{2 u ^{3} - u ^{2} - 1}{u - 1}

Dividir

\frac{2 u ^{3} - u ^{2} - 1}{u - 1} : \frac{2 u ^{3} - u ^{2} - 1}{u - 1} = 2 u^{2} + \frac{u ^{2} - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

2 u^{3} - u^{2} - 1

e o divisor

u - 1 : \frac{2 u ^{3}}{u} = 2 u^{2}

Quociente = 2 u^{2}

Multiplicar

u - 1

por

2 u^{2} : 2 u^{3} - 2 u^{2}

Subtrair

2 u^{3} - 2 u^{2}

2 u^{3} - u^{2} - 1

para obter um novo resto

Resto = u^{2} - 1

Portanto

\frac{2 u ^{3} - u ^{2} - 1}{u - 1} = 2 u^{2} + \frac{u ^{2} - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + \frac{u ^{2} - 1}{u - 1}

Dividir

\frac{u ^{2} - 1}{u - 1} : \frac{u ^{2} - 1}{u - 1} = u + \frac{u - 1}{u - 1}

Dividir os coeficientes dos termos de maior grau do numerador

u^{2} - 1

e o divisor

u - 1 : \frac{u ^{2}}{u} = u

Quociente = u

Multiplicar

u - 1

por

u : u^{2} - u

Subtrair

u^{2} - u

u^{2} - 1

para obter um novo resto

Resto = u - 1

Portanto

\frac{u ^{2} - 1}{u - 1} = u + \frac{u - 1}{u - 1}

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + \frac{u - 1}{u - 1}

Dividir

\frac{u - 1}{u - 1} : \frac{u - 1}{u - 1} = 1

Dividir os coeficientes dos termos de maior grau do numerador

u - 1

e o divisor

u - 1 : \frac{u}{u} = 1

Quociente = 1

Multiplicar

u - 1

por

1 : u - 1

Subtrair

u - 1

u - 1

para obter um novo resto

Resto = 0

Portanto

\frac{u - 1}{u - 1} = 1

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1

= 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1

= (u - 1) (2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1)

= u (u - 1) (2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1)

u (u - 1) (2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1) = 0

Usando o princípio do fator zero: Se

ab = 0

então

a = 0

b = 0

u = 0 or u - 1 = 0 or 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1 = 0

Resolver

u - 1 = 0 : u = 1

u - 1 = 0

Mova

1

para o lado direito

u - 1 = 0

Adicionar

1

a ambos os lados

u - 1 + 1 = 0 + 1

Simplificar

u = 1

u = 1

Resolver

2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1 = 0 :

Sem solução para

u \in R

2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1 = 0

Encontrar uma solução para

2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1 = 0

utilizando o método de Newton-Raphson:

Sem solução para

u \in R

2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1 = 0

Definição de método de Newton-Raphson

f (u) = 2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1

Encontrar

f^{^{'}} (u) : 40 u^{19} + 38 u^{18} + 36 u^{17} + 34 u^{16} + 32 u^{15} + 30 u^{14} + 28 u^{13} + 26 u^{12} + 24 u^{11} + 22 u^{10} + 20 u^{9} + 18 u^{8} + 16 u^{7} + 14 u^{6} + 12 u^{5} + 10 u^{4} + 8 u^{3} + 6 u^{2} + 4 u + 1

\frac{d}{d u} (2 u^{20} + 2 u^{19} + 2 u^{18} + 2 u^{17} + 2 u^{16} + 2 u^{15} + 2 u^{14} + 2 u^{13} + 2 u^{12} + 2 u^{11} + 2 u^{10} + 2 u^{9} + 2 u^{8} + 2 u^{7} + 2 u^{6} + 2 u^{5} + 2 u^{4} + 2 u^{3} + 2 u^{2} + u + 1)

Aplicar a regra da soma/diferença:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (2 u^{20}) + \frac{d}{d u} (2 u^{19}) + \frac{d}{d u} (2 u^{18}) + \frac{d}{d u} (2 u^{17}) + \frac{d}{d u} (2 u^{16}) + \frac{d}{d u} (2 u^{15}) + \frac{d}{d u} (2 u^{14}) + \frac{d}{d u} (2 u^{13}) + \frac{d}{d u} (2 u^{12}) + \frac{d}{d u} (2 u^{11}) + \frac{d}{d u} (2 u^{10}) + \frac{d}{d u} (2 u^{9}) + \frac{d}{d u} (2 u^{8}) + \frac{d}{d u} (2 u^{7}) + \frac{d}{d u} (2 u^{6}) + \frac{d}{d u} (2 u^{5}) + \frac{d}{d u} (2 u^{4}) + \frac{d}{d u} (2 u^{3}) + \frac{d}{d u} (2 u^{2}) + \frac{d u}{d u} + \frac{d}{d u} (1)

\frac{d}{d u} (2 u^{20}) = 40 u^{19}

\frac{d}{d u} (2 u^{20})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{20})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 20 u^{20 - 1}

Simplificar

= 40 u^{19}

\frac{d}{d u} (2 u^{19}) = 38 u^{18}

\frac{d}{d u} (2 u^{19})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{19})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 19 u^{19 - 1}

Simplificar

= 38 u^{18}

\frac{d}{d u} (2 u^{18}) = 36 u^{17}

\frac{d}{d u} (2 u^{18})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{18})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 18 u^{18 - 1}

Simplificar

= 36 u^{17}

\frac{d}{d u} (2 u^{17}) = 34 u^{16}

\frac{d}{d u} (2 u^{17})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{17})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 17 u^{17 - 1}

Simplificar

= 34 u^{16}

\frac{d}{d u} (2 u^{16}) = 32 u^{15}

\frac{d}{d u} (2 u^{16})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{16})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 16 u^{16 - 1}

Simplificar

= 32 u^{15}

\frac{d}{d u} (2 u^{15}) = 30 u^{14}

\frac{d}{d u} (2 u^{15})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{15})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 15 u^{15 - 1}

Simplificar

= 30 u^{14}

\frac{d}{d u} (2 u^{14}) = 28 u^{13}

\frac{d}{d u} (2 u^{14})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{14})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 14 u^{14 - 1}

Simplificar

= 28 u^{13}

\frac{d}{d u} (2 u^{13}) = 26 u^{12}

\frac{d}{d u} (2 u^{13})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{13})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 13 u^{13 - 1}

Simplificar

= 26 u^{12}

\frac{d}{d u} (2 u^{12}) = 24 u^{11}

\frac{d}{d u} (2 u^{12})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{12})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 12 u^{12 - 1}

Simplificar

= 24 u^{11}

\frac{d}{d u} (2 u^{11}) = 22 u^{10}

\frac{d}{d u} (2 u^{11})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{11})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 11 u^{11 - 1}

Simplificar

= 22 u^{10}

\frac{d}{d u} (2 u^{10}) = 20 u^{9}

\frac{d}{d u} (2 u^{10})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{10})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 10 u^{10 - 1}

Simplificar

= 20 u^{9}

\frac{d}{d u} (2 u^{9}) = 18 u^{8}

\frac{d}{d u} (2 u^{9})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{9})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 9 u^{9 - 1}

Simplificar

= 18 u^{8}

\frac{d}{d u} (2 u^{8}) = 16 u^{7}

\frac{d}{d u} (2 u^{8})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{8})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 8 u^{8 - 1}

Simplificar

= 16 u^{7}

\frac{d}{d u} (2 u^{7}) = 14 u^{6}

\frac{d}{d u} (2 u^{7})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{7})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 7 u^{7 - 1}

Simplificar

= 14 u^{6}

\frac{d}{d u} (2 u^{6}) = 12 u^{5}

\frac{d}{d u} (2 u^{6})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{6})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 6 u^{6 - 1}

Simplificar

= 12 u^{5}

\frac{d}{d u} (2 u^{5}) = 10 u^{4}

\frac{d}{d u} (2 u^{5})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{5})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 5 u^{5 - 1}

Simplificar

= 10 u^{4}

\frac{d}{d u} (2 u^{4}) = 8 u^{3}

\frac{d}{d u} (2 u^{4})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{4})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 4 u^{4 - 1}

Simplificar

= 8 u^{3}

\frac{d}{d u} (2 u^{3}) = 6 u^{2}

\frac{d}{d u} (2 u^{3})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{3})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 3 u^{3 - 1}

Simplificar

= 6 u^{2}

\frac{d}{d u} (2 u^{2}) = 4 u

\frac{d}{d u} (2 u^{2})

Retirar a constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d u} (u^{2})

Aplicar a regra da potência:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 u^{2 - 1}

Simplificar

= 4 u

\frac{d u}{d u} = 1

\frac{d u}{d u}

Aplicar a regra da derivação:

\frac{d u}{d u} = 1

= 1

\frac{d}{d u} (1) = 0

\frac{d}{d u} (1)

Derivada de uma constante:

\frac{d}{d x} (a) = 0

= 0

= 40 u^{19} + 38 u^{18} + 36 u^{17} + 34 u^{16} + 32 u^{15} + 30 u^{14} + 28 u^{13} + 26 u^{12} + 24 u^{11} + 22 u^{10} + 20 u^{9} + 18 u^{8} + 16 u^{7} + 14 u^{6} + 12 u^{5} + 10 u^{4} + 8 u^{3} + 6 u^{2} + 4 u + 1 + 0

Simplificar

= 40 u^{19} + 38 u^{18} + 36 u^{17} + 34 u^{16} + 32 u^{15} + 30 u^{14} + 28 u^{13} + 26 u^{12} + 24 u^{11} + 22 u^{10} + 20 u^{9} + 18 u^{8} + 16 u^{7} + 14 u^{6} + 12 u^{5} + 10 u^{4} + 8 u^{3} + 6 u^{2} + 4 u + 1

Seja

u_{0} = - 1

Calcular

u_{n + 1}

até que

Δ u_{n + 1} < 0.000001

u_{1} = - 0.90476 \dots : Δ u_{1} = 0.09523 \dots

f (u_{0}) = 2 (- 1)^{20} + 2 (- 1)^{19} + 2 (- 1)^{18} + 2 (- 1)^{17} + 2 (- 1)^{16} + 2 (- 1)^{15} + 2 (- 1)^{14} + 2 (- 1)^{13} + 2 (- 1)^{12} + 2 (- 1)^{11} + 2 (- 1)^{10} + 2 (- 1)^{9} + 2 (- 1)^{8} + 2 (- 1)^{7} + 2 (- 1)^{6} + 2 (- 1)^{5} + 2 (- 1)^{4} + 2 (- 1)^{3} + 2 (- 1)^{2} + (- 1) + 1 = 2

f^{^{'}} (u_{0}) = 40 (- 1)^{19} + 38 (- 1)^{18} + 36 (- 1)^{17} + 34 (- 1)^{16} + 32 (- 1)^{15} + 30 (- 1)^{14} + 28 (- 1)^{13} + 26 (- 1)^{12} + 24 (- 1)^{11} + 22 (- 1)^{10} + 20 (- 1)^{9} + 18 (- 1)^{8} + 16 (- 1)^{7} + 14 (- 1)^{6} + 12 (- 1)^{5} + 10 (- 1)^{4} + 8 (- 1)^{3} + 6 (- 1)^{2} + 4 (- 1) + 1 = - 21

u_{1} = - 0.90476 \dots

Δ u_{1} = ∣ - 0.90476 \dots - (- 1) ∣ = 0.09523 \dots

Δ u_{1} = 0.09523 \dots

u_{2} = - 0.58245 \dots : Δ u_{2} = 0.32230 \dots

f (u_{1}) = 2 (- 0.90476 \dots)^{20} + 2 (- 0.90476 \dots)^{19} + 2 (- 0.90476 \dots)^{18} + 2 (- 0.90476 \dots)^{17} + 2 (- 0.90476 \dots)^{16} + 2 (- 0.90476 \dots)^{15} + 2 (- 0.90476 \dots)^{14} + 2 (- 0.90476 \dots)^{13} + 2 (- 0.90476 \dots)^{12} + 2 (- 0.90476 \dots)^{11} + 2 (- 0.90476 \dots)^{10} + 2 (- 0.90476 \dots)^{9} + 2 (- 0.90476 \dots)^{8} + 2 (- 0.90476 \dots)^{7} + 2 (- 0.90476 \dots)^{6} + 2 (- 0.90476 \dots)^{5} + 2 (- 0.90476 \dots)^{4} + 2 (- 0.90476 \dots)^{3} + 2 (- 0.90476 \dots)^{2} + (- 0.90476 \dots) + 1 = 1.08311 \dots

f^{^{'}} (u_{1}) = 40 (- 0.90476 \dots)^{19} + 38 (- 0.90476 \dots)^{18} + 36 (- 0.90476 \dots)^{17} + 34 (- 0.90476 \dots)^{16} + 32 (- 0.90476 \dots)^{15} + 30 (- 0.90476 \dots)^{14} + 28 (- 0.90476 \dots)^{13} + 26 (- 0.90476 \dots)^{12} + 24 (- 0.90476 \dots)^{11} + 22 (- 0.90476 \dots)^{10} + 20 (- 0.90476 \dots)^{9} + 18 (- 0.90476 \dots)^{8} + 16 (- 0.90476 \dots)^{7} + 14 (- 0.90476 \dots)^{6} + 12 (- 0.90476 \dots)^{5} + 10 (- 0.90476 \dots)^{4} + 8 (- 0.90476 \dots)^{3} + 6 (- 0.90476 \dots)^{2} + 4 (- 0.90476 \dots) + 1 = - 3.36053 \dots

u_{2} = - 0.58245 \dots

Δ u_{2} = ∣ - 0.58245 \dots - (- 0.90476 \dots) ∣ = 0.32230 \dots

Δ u_{2} = 0.32230 \dots

u_{3} = 3.61022 \dots : Δ u_{3} = 4.19268 \dots

f (u_{2}) = 2 (- 0.58245 \dots)^{20} + 2 (- 0.58245 \dots)^{19} + 2 (- 0.58245 \dots)^{18} + 2 (- 0.58245 \dots)^{17} + 2 (- 0.58245 \dots)^{16} + 2 (- 0.58245 \dots)^{15} + 2 (- 0.58245 \dots)^{14} + 2 (- 0.58245 \dots)^{13} + 2 (- 0.58245 \dots)^{12} + 2 (- 0.58245 \dots)^{11} + 2 (- 0.58245 \dots)^{10} + 2 (- 0.58245 \dots)^{9} + 2 (- 0.58245 \dots)^{8} + 2 (- 0.58245 \dots)^{7} + 2 (- 0.58245 \dots)^{6} + 2 (- 0.58245 \dots)^{5} + 2 (- 0.58245 \dots)^{4} + 2 (- 0.58245 \dots)^{3} + 2 (- 0.58245 \dots)^{2} + (- 0.58245 \dots) + 1 = 0.84632 \dots

f^{^{'}} (u_{2}) = 40 (- 0.58245 \dots)^{19} + 38 (- 0.58245 \dots)^{18} + 36 (- 0.58245 \dots)^{17} + 34 (- 0.58245 \dots)^{16} + 32 (- 0.58245 \dots)^{15} + 30 (- 0.58245 \dots)^{14} + 28 (- 0.58245 \dots)^{13} + 26 (- 0.58245 \dots)^{12} + 24 (- 0.58245 \dots)^{11} + 22 (- 0.58245 \dots)^{10} + 20 (- 0.58245 \dots)^{9} + 18 (- 0.58245 \dots)^{8} + 16 (- 0.58245 \dots)^{7} + 14 (- 0.58245 \dots)^{6} + 12 (- 0.58245 \dots)^{5} + 10 (- 0.58245 \dots)^{4} + 8 (- 0.58245 \dots)^{3} + 6 (- 0.58245 \dots)^{2} + 4 (- 0.58245 \dots) + 1 = - 0.20185 \dots

u_{3} = 3.61022 \dots

Δ u_{3} = ∣ 3.61022 \dots - (- 0.58245 \dots) ∣ = 4.19268 \dots

Δ u_{3} = 4.19268 \dots

u_{4} = 3.42618 \dots : Δ u_{4} = 0.18403 \dots

f (u_{3}) = 2 \cdot 3.61022 \dots^{20} + 2 \cdot 3.61022 \dots^{19} + 2 \cdot 3.61022 \dots^{18} + 2 \cdot 3.61022 \dots^{17} + 2 \cdot 3.61022 \dots^{16} + 2 \cdot 3.61022 \dots^{15} + 2 \cdot 3.61022 \dots^{14} + 2 \cdot 3.61022 \dots^{13} + 2 \cdot 3.61022 \dots^{12} + 2 \cdot 3.61022 \dots^{11} + 2 \cdot 3.61022 \dots^{10} + 2 \cdot 3.61022 \dots^{9} + 2 \cdot 3.61022 \dots^{8} + 2 \cdot 3.61022 \dots^{7} + 2 \cdot 3.61022 \dots^{6} + 2 \cdot 3.61022 \dots^{5} + 2 \cdot 3.61022 \dots^{4} + 2 \cdot 3.61022 \dots^{3} + 2 \cdot 3.61022 \dots^{2} + 3.61022 \dots + 1 = 391356105797.3665

f^{^{'}} (u_{3}) = 40 \cdot 3.61022 \dots^{19} + 38 \cdot 3.61022 \dots^{18} + 36 \cdot 3.61022 \dots^{17} + 34 \cdot 3.61022 \dots^{16} + 32 \cdot 3.61022 \dots^{15} + 30 \cdot 3.61022 \dots^{14} + 28 \cdot 3.61022 \dots^{13} + 26 \cdot 3.61022 \dots^{12} + 24 \cdot 3.61022 \dots^{11} + 22 \cdot 3.61022 \dots^{10} + 20 \cdot 3.61022 \dots^{9} + 18 \cdot 3.61022 \dots^{8} + 16 \cdot 3.61022 \dots^{7} + 14 \cdot 3.61022 \dots^{6} + 12 \cdot 3.61022 \dots^{5} + 10 \cdot 3.61022 \dots^{4} + 8 \cdot 3.61022 \dots^{3} + 6 \cdot 3.61022 \dots^{2} + 4 \cdot 3.61022 \dots + 1 = 2126512839249.2053

u_{4} = 3.42618 \dots

Δ u_{4} = ∣ 3.42618 \dots - 3.61022 \dots ∣ = 0.18403 \dots

Δ u_{4} = 0.18403 \dots

u_{5} = 3.25127 \dots : Δ u_{5} = 0.17491 \dots

f (u_{4}) = 2 \cdot 3.42618 \dots^{20} + 2 \cdot 3.42618 \dots^{19} + 2 \cdot 3.42618 \dots^{18} + 2 \cdot 3.42618 \dots^{17} + 2 \cdot 3.42618 \dots^{16} + 2 \cdot 3.42618 \dots^{15} + 2 \cdot 3.42618 \dots^{14} + 2 \cdot 3.42618 \dots^{13} + 2 \cdot 3.42618 \dots^{12} + 2 \cdot 3.42618 \dots^{11} + 2 \cdot 3.42618 \dots^{10} + 2 \cdot 3.42618 \dots^{9} + 2 \cdot 3.42618 \dots^{8} + 2 \cdot 3.42618 \dots^{7} + 2 \cdot 3.42618 \dots^{6} + 2 \cdot 3.42618 \dots^{5} + 2 \cdot 3.42618 \dots^{4} + 2 \cdot 3.42618 \dots^{3} + 2 \cdot 3.42618 \dots^{2} + 3.42618 \dots + 1 = 140327262334.09973

f^{^{'}} (u_{4}) = 40 \cdot 3.42618 \dots^{19} + 38 \cdot 3.42618 \dots^{18} + 36 \cdot 3.42618 \dots^{17} + 34 \cdot 3.42618 \dots^{16} + 32 \cdot 3.42618 \dots^{15} + 30 \cdot 3.42618 \dots^{14} + 28 \cdot 3.42618 \dots^{13} + 26 \cdot 3.42618 \dots^{12} + 24 \cdot 3.42618 \dots^{11} + 22 \cdot 3.42618 \dots^{10} + 20 \cdot 3.42618 \dots^{9} + 18 \cdot 3.42618 \dots^{8} + 16 \cdot 3.42618 \dots^{7} + 14 \cdot 3.42618 \dots^{6} + 12 \cdot 3.42618 \dots^{5} + 10 \cdot 3.42618 \dots^{4} + 8 \cdot 3.42618 \dots^{3} + 6 \cdot 3.42618 \dots^{2} + 4 \cdot 3.42618 \dots + 1 = 802263679492.2867

u_{5} = 3.25127 \dots

Δ u_{5} = ∣ 3.25127 \dots - 3.42618 \dots ∣ = 0.17491 \dots

Δ u_{5} = 0.17491 \dots

u_{6} = 3.08501 \dots : Δ u_{6} = 0.16625 \dots

f (u_{5}) = 2 \cdot 3.25127 \dots^{20} + 2 \cdot 3.25127 \dots^{19} + 2 \cdot 3.25127 \dots^{18} + 2 \cdot 3.25127 \dots^{17} + 2 \cdot 3.25127 \dots^{16} + 2 \cdot 3.25127 \dots^{15} + 2 \cdot 3.25127 \dots^{14} + 2 \cdot 3.25127 \dots^{13} + 2 \cdot 3.25127 \dots^{12} + 2 \cdot 3.25127 \dots^{11} + 2 \cdot 3.25127 \dots^{10} + 2 \cdot 3.25127 \dots^{9} + 2 \cdot 3.25127 \dots^{8} + 2 \cdot 3.25127 \dots^{7} + 2 \cdot 3.25127 \dots^{6} + 2 \cdot 3.25127 \dots^{5} + 2 \cdot 3.25127 \dots^{4} + 2 \cdot 3.25127 \dots^{3} + 2 \cdot 3.25127 \dots^{2} + 3.25127 \dots + 1 = 50318521009.06572

f^{^{'}} (u_{5}) = 40 \cdot 3.25127 \dots^{19} + 38 \cdot 3.25127 \dots^{18} + 36 \cdot 3.25127 \dots^{17} + 34 \cdot 3.25127 \dots^{16} + 32 \cdot 3.25127 \dots^{15} + 30 \cdot 3.25127 \dots^{14} + 28 \cdot 3.25127 \dots^{13} + 26 \cdot 3.25127 \dots^{12} + 24 \cdot 3.25127 \dots^{11} + 22 \cdot 3.25127 \dots^{10} + 20 \cdot 3.25127 \dots^{9} + 18 \cdot 3.25127 \dots^{8} + 16 \cdot 3.25127 \dots^{7} + 14 \cdot 3.25127 \dots^{6} + 12 \cdot 3.25127 \dots^{5} + 10 \cdot 3.25127 \dots^{4} + 8 \cdot 3.25127 \dots^{3} + 6 \cdot 3.25127 \dots^{2} + 4 \cdot 3.25127 \dots + 1 = 302656481865.62994

u_{6} = 3.08501 \dots

Δ u_{6} = ∣ 3.08501 \dots - 3.25127 \dots ∣ = 0.16625 \dots

Δ u_{6} = 0.16625 \dots

u_{7} = 2.92697 \dots : Δ u_{7} = 0.15804 \dots

f (u_{6}) = 2 \cdot 3.08501 \dots^{20} + 2 \cdot 3.08501 \dots^{19} + 2 \cdot 3.08501 \dots^{18} + 2 \cdot 3.08501 \dots^{17} + 2 \cdot 3.08501 \dots^{16} + 2 \cdot 3.08501 \dots^{15} + 2 \cdot 3.08501 \dots^{14} + 2 \cdot 3.08501 \dots^{13} + 2 \cdot 3.08501 \dots^{12} + 2 \cdot 3.08501 \dots^{11} + 2 \cdot 3.08501 \dots^{10} + 2 \cdot 3.08501 \dots^{9} + 2 \cdot 3.08501 \dots^{8} + 2 \cdot 3.08501 \dots^{7} + 2 \cdot 3.08501 \dots^{6} + 2 \cdot 3.08501 \dots^{5} + 2 \cdot 3.08501 \dots^{4} + 2 \cdot 3.08501 \dots^{3} + 2 \cdot 3.08501 \dots^{2} + 3.08501 \dots + 1 = 18043992829.22628

f^{^{'}} (u_{6}) = 40 \cdot 3.08501 \dots^{19} + 38 \cdot 3.08501 \dots^{18} + 36 \cdot 3.08501 \dots^{17} + 34 \cdot 3.08501 \dots^{16} + 32 \cdot 3.08501 \dots^{15} + 30 \cdot 3.08501 \dots^{14} + 28 \cdot 3.08501 \dots^{13} + 26 \cdot 3.08501 \dots^{12} + 24 \cdot 3.08501 \dots^{11} + 22 \cdot 3.08501 \dots^{10} + 20 \cdot 3.08501 \dots^{9} + 18 \cdot 3.08501 \dots^{8} + 16 \cdot 3.08501 \dots^{7} + 14 \cdot 3.08501 \dots^{6} + 12 \cdot 3.08501 \dots^{5} + 10 \cdot 3.08501 \dots^{4} + 8 \cdot 3.08501 \dots^{3} + 6 \cdot 3.08501 \dots^{2} + 4 \cdot 3.08501 \dots + 1 = 114172983680.20372

u_{7} = 2.92697 \dots

Δ u_{7} = ∣ 2.92697 \dots - 3.08501 \dots ∣ = 0.15804 \dots

Δ u_{7} = 0.15804 \dots

u_{8} = 2.77673 \dots : Δ u_{8} = 0.15024 \dots

f (u_{7}) = 2 \cdot 2.92697 \dots^{20} + 2 \cdot 2.92697 \dots^{19} + 2 \cdot 2.92697 \dots^{18} + 2 \cdot 2.92697 \dots^{17} + 2 \cdot 2.92697 \dots^{16} + 2 \cdot 2.92697 \dots^{15} + 2 \cdot 2.92697 \dots^{14} + 2 \cdot 2.92697 \dots^{13} + 2 \cdot 2.92697 \dots^{12} + 2 \cdot 2.92697 \dots^{11} + 2 \cdot 2.92697 \dots^{10} + 2 \cdot 2.92697 \dots^{9} + 2 \cdot 2.92697 \dots^{8} + 2 \cdot 2.92697 \dots^{7} + 2 \cdot 2.92697 \dots^{6} + 2 \cdot 2.92697 \dots^{5} + 2 \cdot 2.92697 \dots^{4} + 2 \cdot 2.92697 \dots^{3} + 2 \cdot 2.92697 \dots^{2} + 2.92697 \dots + 1 = 6470833347.00402

f^{^{'}} (u_{7}) = 40 \cdot 2.92697 \dots^{19} + 38 \cdot 2.92697 \dots^{18} + 36 \cdot 2.92697 \dots^{17} + 34 \cdot 2.92697 \dots^{16} + 32 \cdot 2.92697 \dots^{15} + 30 \cdot 2.92697 \dots^{14} + 28 \cdot 2.92697 \dots^{13} + 26 \cdot 2.92697 \dots^{12} + 24 \cdot 2.92697 \dots^{11} + 22 \cdot 2.92697 \dots^{10} + 20 \cdot 2.92697 \dots^{9} + 18 \cdot 2.92697 \dots^{8} + 16 \cdot 2.92697 \dots^{7} + 14 \cdot 2.92697 \dots^{6} + 12 \cdot 2.92697 \dots^{5} + 10 \cdot 2.92697 \dots^{4} + 8 \cdot 2.92697 \dots^{3} + 6 \cdot 2.92697 \dots^{2} + 4 \cdot 2.92697 \dots + 1 = 43067856733.97665

u_{8} = 2.77673 \dots

Δ u_{8} = ∣ 2.77673 \dots - 2.92697 \dots ∣ = 0.15024 \dots

Δ u_{8} = 0.15024 \dots

u_{9} = 2.63387 \dots : Δ u_{9} = 0.14285 \dots

f (u_{8}) = 2 \cdot 2.77673 \dots^{20} + 2 \cdot 2.77673 \dots^{19} + 2 \cdot 2.77673 \dots^{18} + 2 \cdot 2.77673 \dots^{17} + 2 \cdot 2.77673 \dots^{16} + 2 \cdot 2.77673 \dots^{15} + 2 \cdot 2.77673 \dots^{14} + 2 \cdot 2.77673 \dots^{13} + 2 \cdot 2.77673 \dots^{12} + 2 \cdot 2.77673 \dots^{11} + 2 \cdot 2.77673 \dots^{10} + 2 \cdot 2.77673 \dots^{9} + 2 \cdot 2.77673 \dots^{8} + 2 \cdot 2.77673 \dots^{7} + 2 \cdot 2.77673 \dots^{6} + 2 \cdot 2.77673 \dots^{5} + 2 \cdot 2.77673 \dots^{4} + 2 \cdot 2.77673 \dots^{3} + 2 \cdot 2.77673 \dots^{2} + 2.77673 \dots + 1 = 2320680563.35344 \dots

f^{^{'}} (u_{8}) = 40 \cdot 2.77673 \dots^{19} + 38 \cdot 2.77673 \dots^{18} + 36 \cdot 2.77673 \dots^{17} + 34 \cdot 2.77673 \dots^{16} + 32 \cdot 2.77673 \dots^{15} + 30 \cdot 2.77673 \dots^{14} + 28 \cdot 2.77673 \dots^{13} + 26 \cdot 2.77673 \dots^{12} + 24 \cdot 2.77673 \dots^{11} + 22 \cdot 2.77673 \dots^{10} + 20 \cdot 2.77673 \dots^{9} + 18 \cdot 2.77673 \dots^{8} + 16 \cdot 2.77673 \dots^{7} + 14 \cdot 2.77673 \dots^{6} + 12 \cdot 2.77673 \dots^{5} + 10 \cdot 2.77673 \dots^{4} + 8 \cdot 2.77673 \dots^{3} + 6 \cdot 2.77673 \dots^{2} + 4 \cdot 2.77673 \dots + 1 = 16244812495.12528

u_{9} = 2.63387 \dots

Δ u_{9} = ∣ 2.63387 \dots - 2.77673 \dots ∣ = 0.14285 \dots

Δ u_{9} = 0.14285 \dots

u_{10} = 2.49802 \dots : Δ u_{10} = 0.13585 \dots

f (u_{9}) = 2 \cdot 2.63387 \dots^{20} + 2 \cdot 2.63387 \dots^{19} + 2 \cdot 2.63387 \dots^{18} + 2 \cdot 2.63387 \dots^{17} + 2 \cdot 2.63387 \dots^{16} + 2 \cdot 2.63387 \dots^{15} + 2 \cdot 2.63387 \dots^{14} + 2 \cdot 2.63387 \dots^{13} + 2 \cdot 2.63387 \dots^{12} + 2 \cdot 2.63387 \dots^{11} + 2 \cdot 2.63387 \dots^{10} + 2 \cdot 2.63387 \dots^{9} + 2 \cdot 2.63387 \dots^{8} + 2 \cdot 2.63387 \dots^{7} + 2 \cdot 2.63387 \dots^{6} + 2 \cdot 2.63387 \dots^{5} + 2 \cdot 2.63387 \dots^{4} + 2 \cdot 2.63387 \dots^{3} + 2 \cdot 2.63387 \dots^{2} + 2.63387 \dots + 1 = 832346488.77442 \dots

f^{^{'}} (u_{9}) = 40 \cdot 2.63387 \dots^{19} + 38 \cdot 2.63387 \dots^{18} + 36 \cdot 2.63387 \dots^{17} + 34 \cdot 2.63387 \dots^{16} + 32 \cdot 2.63387 \dots^{15} + 30 \cdot 2.63387 \dots^{14} + 28 \cdot 2.63387 \dots^{13} + 26 \cdot 2.63387 \dots^{12} + 24 \cdot 2.63387 \dots^{11} + 22 \cdot 2.63387 \dots^{10} + 20 \cdot 2.63387 \dots^{9} + 18 \cdot 2.63387 \dots^{8} + 16 \cdot 2.63387 \dots^{7} + 14 \cdot 2.63387 \dots^{6} + 12 \cdot 2.63387 \dots^{5} + 10 \cdot 2.63387 \dots^{4} + 8 \cdot 2.63387 \dots^{3} + 6 \cdot 2.63387 \dots^{2} + 4 \cdot 2.63387 \dots + 1 = 6126907579.45191 \dots

u_{10} = 2.49802 \dots

Δ u_{10} = ∣ 2.49802 \dots - 2.63387 \dots ∣ = 0.13585 \dots

Δ u_{10} = 0.13585 \dots

u_{11} = 2.36880 \dots : Δ u_{11} = 0.12921 \dots

f (u_{10}) = 2 \cdot 2.49802 \dots^{20} + 2 \cdot 2.49802 \dots^{19} + 2 \cdot 2.49802 \dots^{18} + 2 \cdot 2.49802 \dots^{17} + 2 \cdot 2.49802 \dots^{16} + 2 \cdot 2.49802 \dots^{15} + 2 \cdot 2.49802 \dots^{14} + 2 \cdot 2.49802 \dots^{13} + 2 \cdot 2.49802 \dots^{12} + 2 \cdot 2.49802 \dots^{11} + 2 \cdot 2.49802 \dots^{10} + 2 \cdot 2.49802 \dots^{9} + 2 \cdot 2.49802 \dots^{8} + 2 \cdot 2.49802 \dots^{7} + 2 \cdot 2.49802 \dots^{6} + 2 \cdot 2.49802 \dots^{5} + 2 \cdot 2.49802 \dots^{4} + 2 \cdot 2.49802 \dots^{3} + 2 \cdot 2.49802 \dots^{2} + 2.49802 \dots + 1 = 298561855.74542 \dots

f^{^{'}} (u_{10}) = 40 \cdot 2.49802 \dots^{19} + 38 \cdot 2.49802 \dots^{18} + 36 \cdot 2.49802 \dots^{17} + 34 \cdot 2.49802 \dots^{16} + 32 \cdot 2.49802 \dots^{15} + 30 \cdot 2.49802 \dots^{14} + 28 \cdot 2.49802 \dots^{13} + 26 \cdot 2.49802 \dots^{12} + 24 \cdot 2.49802 \dots^{11} + 22 \cdot 2.49802 \dots^{10} + 20 \cdot 2.49802 \dots^{9} + 18 \cdot 2.49802 \dots^{8} + 16 \cdot 2.49802 \dots^{7} + 14 \cdot 2.49802 \dots^{6} + 12 \cdot 2.49802 \dots^{5} + 10 \cdot 2.49802 \dots^{4} + 8 \cdot 2.49802 \dots^{3} + 6 \cdot 2.49802 \dots^{2} + 4 \cdot 2.49802 \dots + 1 = 2310601127.77513 \dots

u_{11} = 2.36880 \dots

Δ u_{11} = ∣ 2.36880 \dots - 2.49802 \dots ∣ = 0.12921 \dots

Δ u_{11} = 0.12921 \dots

u_{12} = 2.24587 \dots : Δ u_{12} = 0.12293 \dots

f (u_{11}) = 2 \cdot 2.36880 \dots^{20} + 2 \cdot 2.36880 \dots^{19} + 2 \cdot 2.36880 \dots^{18} + 2 \cdot 2.36880 \dots^{17} + 2 \cdot 2.36880 \dots^{16} + 2 \cdot 2.36880 \dots^{15} + 2 \cdot 2.36880 \dots^{14} + 2 \cdot 2.36880 \dots^{13} + 2 \cdot 2.36880 \dots^{12} + 2 \cdot 2.36880 \dots^{11} + 2 \cdot 2.36880 \dots^{10} + 2 \cdot 2.36880 \dots^{9} + 2 \cdot 2.36880 \dots^{8} + 2 \cdot 2.36880 \dots^{7} + 2 \cdot 2.36880 \dots^{6} + 2 \cdot 2.36880 \dots^{5} + 2 \cdot 2.36880 \dots^{4} + 2 \cdot 2.36880 \dots^{3} + 2 \cdot 2.36880 \dots^{2} + 2.36880 \dots + 1 = 107106520.29046 \dots

f^{^{'}} (u_{11}) = 40 \cdot 2.36880 \dots^{19} + 38 \cdot 2.36880 \dots^{18} + 36 \cdot 2.36880 \dots^{17} + 34 \cdot 2.36880 \dots^{16} + 32 \cdot 2.36880 \dots^{15} + 30 \cdot 2.36880 \dots^{14} + 28 \cdot 2.36880 \dots^{13} + 26 \cdot 2.36880 \dots^{12} + 24 \cdot 2.36880 \dots^{11} + 22 \cdot 2.36880 \dots^{10} + 20 \cdot 2.36880 \dots^{9} + 18 \cdot 2.36880 \dots^{8} + 16 \cdot 2.36880 \dots^{7} + 14 \cdot 2.36880 \dots^{6} + 12 \cdot 2.36880 \dots^{5} + 10 \cdot 2.36880 \dots^{4} + 8 \cdot 2.36880 \dots^{3} + 6 \cdot 2.36880 \dots^{2} + 4 \cdot 2.36880 \dots + 1 = 871274563.57524 \dots

u_{12} = 2.24587 \dots

Δ u_{12} = ∣ 2.24587 \dots - 2.36880 \dots ∣ = 0.12293 \dots

Δ u_{12} = 0.12293 \dots

u_{13} = 2.12888 \dots : Δ u_{13} = 0.11698 \dots

f (u_{12}) = 2 \cdot 2.24587 \dots^{20} + 2 \cdot 2.24587 \dots^{19} + 2 \cdot 2.24587 \dots^{18} + 2 \cdot 2.24587 \dots^{17} + 2 \cdot 2.24587 \dots^{16} + 2 \cdot 2.24587 \dots^{15} + 2 \cdot 2.24587 \dots^{14} + 2 \cdot 2.24587 \dots^{13} + 2 \cdot 2.24587 \dots^{12} + 2 \cdot 2.24587 \dots^{11} + 2 \cdot 2.24587 \dots^{10} + 2 \cdot 2.24587 \dots^{9} + 2 \cdot 2.24587 \dots^{8} + 2 \cdot 2.24587 \dots^{7} + 2 \cdot 2.24587 \dots^{6} + 2 \cdot 2.24587 \dots^{5} + 2 \cdot 2.24587 \dots^{4} + 2 \cdot 2.24587 \dots^{3} + 2 \cdot 2.24587 \dots^{2} + 2.24587 \dots + 1 = 38429268.19821 \dots

f^{^{'}} (u_{12}) = 40 \cdot 2.24587 \dots^{19} + 38 \cdot 2.24587 \dots^{18} + 36 \cdot 2.24587 \dots^{17} + 34 \cdot 2.24587 \dots^{16} + 32 \cdot 2.24587 \dots^{15} + 30 \cdot 2.24587 \dots^{14} + 28 \cdot 2.24587 \dots^{13} + 26 \cdot 2.24587 \dots^{12} + 24 \cdot 2.24587 \dots^{11} + 22 \cdot 2.24587 \dots^{10} + 20 \cdot 2.24587 \dots^{9} + 18 \cdot 2.24587 \dots^{8} + 16 \cdot 2.24587 \dots^{7} + 14 \cdot 2.24587 \dots^{6} + 12 \cdot 2.24587 \dots^{5} + 10 \cdot 2.24587 \dots^{4} + 8 \cdot 2.24587 \dots^{3} + 6 \cdot 2.24587 \dots^{2} + 4 \cdot 2.24587 \dots + 1 = 328486438.92554 \dots

u_{13} = 2.12888 \dots

Δ u_{13} = ∣ 2.12888 \dots - 2.24587 \dots ∣ = 0.11698 \dots

Δ u_{13} = 0.11698 \dots

u_{14} = 2.01751 \dots : Δ u_{14} = 0.11137 \dots

f (u_{13}) = 2 \cdot 2.12888 \dots^{20} + 2 \cdot 2.12888 \dots^{19} + 2 \cdot 2.12888 \dots^{18} + 2 \cdot 2.12888 \dots^{17} + 2 \cdot 2.12888 \dots^{16} + 2 \cdot 2.12888 \dots^{15} + 2 \cdot 2.12888 \dots^{14} + 2 \cdot 2.12888 \dots^{13} + 2 \cdot 2.12888 \dots^{12} + 2 \cdot 2.12888 \dots^{11} + 2 \cdot 2.12888 \dots^{10} + 2 \cdot 2.12888 \dots^{9} + 2 \cdot 2.12888 \dots^{8} + 2 \cdot 2.12888 \dots^{7} + 2 \cdot 2.12888 \dots^{6} + 2 \cdot 2.12888 \dots^{5} + 2 \cdot 2.12888 \dots^{4} + 2 \cdot 2.12888 \dots^{3} + 2 \cdot 2.12888 \dots^{2} + 2.12888 \dots + 1 = 13790835.58464 \dots

f^{^{'}} (u_{13}) = 40 \cdot 2.12888 \dots^{19} + 38 \cdot 2.12888 \dots^{18} + 36 \cdot 2.12888 \dots^{17} + 34 \cdot 2.12888 \dots^{16} + 32 \cdot 2.12888 \dots^{15} + 30 \cdot 2.12888 \dots^{14} + 28 \cdot 2.12888 \dots^{13} + 26 \cdot 2.12888 \dots^{12} + 24 \cdot 2.12888 \dots^{11} + 22 \cdot 2.12888 \dots^{10} + 20 \cdot 2.12888 \dots^{9} + 18 \cdot 2.12888 \dots^{8} + 16 \cdot 2.12888 \dots^{7} + 14 \cdot 2.12888 \dots^{6} + 12 \cdot 2.12888 \dots^{5} + 10 \cdot 2.12888 \dots^{4} + 8 \cdot 2.12888 \dots^{3} + 6 \cdot 2.12888 \dots^{2} + 4 \cdot 2.12888 \dots + 1 = 123820714.41332 \dots

u_{14} = 2.01751 \dots

Δ u_{14} = ∣ 2.01751 \dots - 2.12888 \dots ∣ = 0.11137 \dots

Δ u_{14} = 0.11137 \dots

u_{15} = 1.91142 \dots : Δ u_{15} = 0.10608 \dots

f (u_{14}) = 2 \cdot 2.01751 \dots^{20} + 2 \cdot 2.01751 \dots^{19} + 2 \cdot 2.01751 \dots^{18} + 2 \cdot 2.01751 \dots^{17} + 2 \cdot 2.01751 \dots^{16} + 2 \cdot 2.01751 \dots^{15} + 2 \cdot 2.01751 \dots^{14} + 2 \cdot 2.01751 \dots^{13} + 2 \cdot 2.01751 \dots^{12} + 2 \cdot 2.01751 \dots^{11} + 2 \cdot 2.01751 \dots^{10} + 2 \cdot 2.01751 \dots^{9} + 2 \cdot 2.01751 \dots^{8} + 2 \cdot 2.01751 \dots^{7} + 2 \cdot 2.01751 \dots^{6} + 2 \cdot 2.01751 \dots^{5} + 2 \cdot 2.01751 \dots^{4} + 2 \cdot 2.01751 \dots^{3} + 2 \cdot 2.01751 \dots^{2} + 2.01751 \dots + 1 = 4950229.82773 \dots

f^{^{'}} (u_{14}) = 40 \cdot 2.01751 \dots^{19} + 38 \cdot 2.01751 \dots^{18} + 36 \cdot 2.01751 \dots^{17} + 34 \cdot 2.01751 \dots^{16} + 32 \cdot 2.01751 \dots^{15} + 30 \cdot 2.01751 \dots^{14} + 28 \cdot 2.01751 \dots^{13} + 26 \cdot 2.01751 \dots^{12} + 24 \cdot 2.01751 \dots^{11} + 22 \cdot 2.01751 \dots^{10} + 20 \cdot 2.01751 \dots^{9} + 18 \cdot 2.01751 \dots^{8} + 16 \cdot 2.01751 \dots^{7} + 14 \cdot 2.01751 \dots^{6} + 12 \cdot 2.01751 \dots^{5} + 10 \cdot 2.01751 \dots^{4} + 8 \cdot 2.01751 \dots^{3} + 6 \cdot 2.01751 \dots^{2} + 4 \cdot 2.01751 \dots + 1 = 46661280.69367 \dots

u_{15} = 1.91142 \dots

Δ u_{15} = ∣ 1.91142 \dots - 2.01751 \dots ∣ = 0.10608 \dots

Δ u_{15} = 0.10608 \dots

u_{16} = 1.81030 \dots : Δ u_{16} = 0.10111 \dots

f (u_{15}) = 2 \cdot 1.91142 \dots^{20} + 2 \cdot 1.91142 \dots^{19} + 2 \cdot 1.91142 \dots^{18} + 2 \cdot 1.91142 \dots^{17} + 2 \cdot 1.91142 \dots^{16} + 2 \cdot 1.91142 \dots^{15} + 2 \cdot 1.91142 \dots^{14} + 2 \cdot 1.91142 \dots^{13} + 2 \cdot 1.91142 \dots^{12} + 2 \cdot 1.91142 \dots^{11} + 2 \cdot 1.91142 \dots^{10} + 2 \cdot 1.91142 \dots^{9} + 2 \cdot 1.91142 \dots^{8} + 2 \cdot 1.91142 \dots^{7} + 2 \cdot 1.91142 \dots^{6} + 2 \cdot 1.91142 \dots^{5} + 2 \cdot 1.91142 \dots^{4} + 2 \cdot 1.91142 \dots^{3} + 2 \cdot 1.91142 \dots^{2} + 1.91142 \dots + 1 = 1777460.56654 \dots

f^{^{'}} (u_{15}) = 40 \cdot 1.91142 \dots^{19} + 38 \cdot 1.91142 \dots^{18} + 36 \cdot 1.91142 \dots^{17} + 34 \cdot 1.91142 \dots^{16} + 32 \cdot 1.91142 \dots^{15} + 30 \cdot 1.91142 \dots^{14} + 28 \cdot 1.91142 \dots^{13} + 26 \cdot 1.91142 \dots^{12} + 24 \cdot 1.91142 \dots^{11} + 22 \cdot 1.91142 \dots^{10} + 20 \cdot 1.91142 \dots^{9} + 18 \cdot 1.91142 \dots^{8} + 16 \cdot 1.91142 \dots^{7} + 14 \cdot 1.91142 \dots^{6} + 12 \cdot 1.91142 \dots^{5} + 10 \cdot 1.91142 \dots^{4} + 8 \cdot 1.91142 \dots^{3} + 6 \cdot 1.91142 \dots^{2} + 4 \cdot 1.91142 \dots + 1 = 17578062.54966 \dots

u_{16} = 1.81030 \dots

Δ u_{16} = ∣ 1.81030 \dots - 1.91142 \dots ∣ = 0.10111 \dots

Δ u_{16} = 0.10111 \dots

u_{17} = 1.71383 \dots : Δ u_{17} = 0.09646 \dots

f (u_{16}) = 2 \cdot 1.81030 \dots^{20} + 2 \cdot 1.81030 \dots^{19} + 2 \cdot 1.81030 \dots^{18} + 2 \cdot 1.81030 \dots^{17} + 2 \cdot 1.81030 \dots^{16} + 2 \cdot 1.81030 \dots^{15} + 2 \cdot 1.81030 \dots^{14} + 2 \cdot 1.81030 \dots^{13} + 2 \cdot 1.81030 \dots^{12} + 2 \cdot 1.81030 \dots^{11} + 2 \cdot 1.81030 \dots^{10} + 2 \cdot 1.81030 \dots^{9} + 2 \cdot 1.81030 \dots^{8} + 2 \cdot 1.81030 \dots^{7} + 2 \cdot 1.81030 \dots^{6} + 2 \cdot 1.81030 \dots^{5} + 2 \cdot 1.81030 \dots^{4} + 2 \cdot 1.81030 \dots^{3} + 2 \cdot 1.81030 \dots^{2} + 1.81030 \dots + 1 = 638502.05884 \dots

f^{^{'}} (u_{16}) = 40 \cdot 1.81030 \dots^{19} + 38 \cdot 1.81030 \dots^{18} + 36 \cdot 1.81030 \dots^{17} + 34 \cdot 1.81030 \dots^{16} + 32 \cdot 1.81030 \dots^{15} + 30 \cdot 1.81030 \dots^{14} + 28 \cdot 1.81030 \dots^{13} + 26 \cdot 1.81030 \dots^{12} + 24 \cdot 1.81030 \dots^{11} + 22 \cdot 1.81030 \dots^{10} + 20 \cdot 1.81030 \dots^{9} + 18 \cdot 1.81030 \dots^{8} + 16 \cdot 1.81030 \dots^{7} + 14 \cdot 1.81030 \dots^{6} + 12 \cdot 1.81030 \dots^{5} + 10 \cdot 1.81030 \dots^{4} + 8 \cdot 1.81030 \dots^{3} + 6 \cdot 1.81030 \dots^{2} + 4 \cdot 1.81030 \dots + 1 = 6618867.78758 \dots

u_{17} = 1.71383 \dots

Δ u_{17} = ∣ 1.71383 \dots - 1.81030 \dots ∣ = 0.09646 \dots

Δ u_{17} = 0.09646 \dots

u_{18} = 1.62169 \dots : Δ u_{18} = 0.09214 \dots

f (u_{17}) = 2 \cdot 1.71383 \dots^{20} + 2 \cdot 1.71383 \dots^{19} + 2 \cdot 1.71383 \dots^{18} + 2 \cdot 1.71383 \dots^{17} + 2 \cdot 1.71383 \dots^{16} + 2 \cdot 1.71383 \dots^{15} + 2 \cdot 1.71383 \dots^{14} + 2 \cdot 1.71383 \dots^{13} + 2 \cdot 1.71383 \dots^{12} + 2 \cdot 1.71383 \dots^{11} + 2 \cdot 1.71383 \dots^{10} + 2 \cdot 1.71383 \dots^{9} + 2 \cdot 1.71383 \dots^{8} + 2 \cdot 1.71383 \dots^{7} + 2 \cdot 1.71383 \dots^{6} + 2 \cdot 1.71383 \dots^{5} + 2 \cdot 1.71383 \dots^{4} + 2 \cdot 1.71383 \dots^{3} + 2 \cdot 1.71383 \dots^{2} + 1.71383 \dots + 1 = 229500.02828 \dots

f^{^{'}} (u_{17}) = 40 \cdot 1.71383 \dots^{19} + 38 \cdot 1.71383 \dots^{18} + 36 \cdot 1.71383 \dots^{17} + 34 \cdot 1.71383 \dots^{16} + 32 \cdot 1.71383 \dots^{15} + 30 \cdot 1.71383 \dots^{14} + 28 \cdot 1.71383 \dots^{13} + 26 \cdot 1.71383 \dots^{12} + 24 \cdot 1.71383 \dots^{11} + 22 \cdot 1.71383 \dots^{10} + 20 \cdot 1.71383 \dots^{9} + 18 \cdot 1.71383 \dots^{8} + 16 \cdot 1.71383 \dots^{7} + 14 \cdot 1.71383 \dots^{6} + 12 \cdot 1.71383 \dots^{5} + 10 \cdot 1.71383 \dots^{4} + 8 \cdot 1.71383 \dots^{3} + 6 \cdot 1.71383 \dots^{2} + 4 \cdot 1.71383 \dots + 1 = 2490671.57675 \dots

u_{18} = 1.62169 \dots

Δ u_{18} = ∣ 1.62169 \dots - 1.71383 \dots ∣ = 0.09214 \dots

Δ u_{18} = 0.09214 \dots

u_{19} = 1.53352 \dots : Δ u_{19} = 0.08816 \dots

f (u_{18}) = 2 \cdot 1.62169 \dots^{20} + 2 \cdot 1.62169 \dots^{19} + 2 \cdot 1.62169 \dots^{18} + 2 \cdot 1.62169 \dots^{17} + 2 \cdot 1.62169 \dots^{16} + 2 \cdot 1.62169 \dots^{15} + 2 \cdot 1.62169 \dots^{14} + 2 \cdot 1.62169 \dots^{13} + 2 \cdot 1.62169 \dots^{12} + 2 \cdot 1.62169 \dots^{11} + 2 \cdot 1.62169 \dots^{10} + 2 \cdot 1.62169 \dots^{9} + 2 \cdot 1.62169 \dots^{8} + 2 \cdot 1.62169 \dots^{7} + 2 \cdot 1.62169 \dots^{6} + 2 \cdot 1.62169 \dots^{5} + 2 \cdot 1.62169 \dots^{4} + 2 \cdot 1.62169 \dots^{3} + 2 \cdot 1.62169 \dots^{2} + 1.62169 \dots + 1 = 82559.70843 \dots

f^{^{'}} (u_{18}) = 40 \cdot 1.62169 \dots^{19} + 38 \cdot 1.62169 \dots^{18} + 36 \cdot 1.62169 \dots^{17} + 34 \cdot 1.62169 \dots^{16} + 32 \cdot 1.62169 \dots^{15} + 30 \cdot 1.62169 \dots^{14} + 28 \cdot 1.62169 \dots^{13} + 26 \cdot 1.62169 \dots^{12} + 24 \cdot 1.62169 \dots^{11} + 22 \cdot 1.62169 \dots^{10} + 20 \cdot 1.62169 \dots^{9} + 18 \cdot 1.62169 \dots^{8} + 16 \cdot 1.62169 \dots^{7} + 14 \cdot 1.62169 \dots^{6} + 12 \cdot 1.62169 \dots^{5} + 10 \cdot 1.62169 \dots^{4} + 8 \cdot 1.62169 \dots^{3} + 6 \cdot 1.62169 \dots^{2} + 4 \cdot 1.62169 \dots + 1 = 936373.05744 \dots

u_{19} = 1.53352 \dots

Δ u_{19} = ∣ 1.53352 \dots - 1.62169 \dots ∣ = 0.08816 \dots

Δ u_{19} = 0.08816 \dots

u_{20} = 1.44893 \dots : Δ u_{20} = 0.08458 \dots

f (u_{19}) = 2 \cdot 1.53352 \dots^{20} + 2 \cdot 1.53352 \dots^{19} + 2 \cdot 1.53352 \dots^{18} + 2 \cdot 1.53352 \dots^{17} + 2 \cdot 1.53352 \dots^{16} + 2 \cdot 1.53352 \dots^{15} + 2 \cdot 1.53352 \dots^{14} + 2 \cdot 1.53352 \dots^{13} + 2 \cdot 1.53352 \dots^{12} + 2 \cdot 1.53352 \dots^{11} + 2 \cdot 1.53352 \dots^{10} + 2 \cdot 1.53352 \dots^{9} + 2 \cdot 1.53352 \dots^{8} + 2 \cdot 1.53352 \dots^{7} + 2 \cdot 1.53352 \dots^{6} + 2 \cdot 1.53352 \dots^{5} + 2 \cdot 1.53352 \dots^{4} + 2 \cdot 1.53352 \dots^{3} + 2 \cdot 1.53352 \dots^{2} + 1.53352 \dots + 1 = 29736.26727 \dots

f^{^{'}} (u_{19}) = 40 \cdot 1.53352 \dots^{19} + 38 \cdot 1.53352 \dots^{18} + 36 \cdot 1.53352 \dots^{17} + 34 \cdot 1.53352 \dots^{16} + 32 \cdot 1.53352 \dots^{15} + 30 \cdot 1.53352 \dots^{14} + 28 \cdot 1.53352 \dots^{13} + 26 \cdot 1.53352 \dots^{12} + 24 \cdot 1.53352 \dots^{11} + 22 \cdot 1.53352 \dots^{10} + 20 \cdot 1.53352 \dots^{9} + 18 \cdot 1.53352 \dots^{8} + 16 \cdot 1.53352 \dots^{7} + 14 \cdot 1.53352 \dots^{6} + 12 \cdot 1.53352 \dots^{5} + 10 \cdot 1.53352 \dots^{4} + 8 \cdot 1.53352 \dots^{3} + 6 \cdot 1.53352 \dots^{2} + 4 \cdot 1.53352 \dots + 1 = 351551.64069 \dots

u_{20} = 1.44893 \dots

Δ u_{20} = ∣ 1.44893 \dots - 1.53352 \dots ∣ = 0.08458 \dots

Δ u_{20} = 0.08458 \dots

u_{21} = 1.36746 \dots : Δ u_{21} = 0.08146 \dots

f (u_{20}) = 2 \cdot 1.44893 \dots^{20} + 2 \cdot 1.44893 \dots^{19} + 2 \cdot 1.44893 \dots^{18} + 2 \cdot 1.44893 \dots^{17} + 2 \cdot 1.44893 \dots^{16} + 2 \cdot 1.44893 \dots^{15} + 2 \cdot 1.44893 \dots^{14} + 2 \cdot 1.44893 \dots^{13} + 2 \cdot 1.44893 \dots^{12} + 2 \cdot 1.44893 \dots^{11} + 2 \cdot 1.44893 \dots^{10} + 2 \cdot 1.44893 \dots^{9} + 2 \cdot 1.44893 \dots^{8} + 2 \cdot 1.44893 \dots^{7} + 2 \cdot 1.44893 \dots^{6} + 2 \cdot 1.44893 \dots^{5} + 2 \cdot 1.44893 \dots^{4} + 2 \cdot 1.44893 \dots^{3} + 2 \cdot 1.44893 \dots^{2} + 1.44893 \dots + 1 = 10730.28828 \dots

f^{^{'}} (u_{20}) = 40 \cdot 1.44893 \dots^{19} + 38 \cdot 1.44893 \dots^{18} + 36 \cdot 1.44893 \dots^{17} + 34 \cdot 1.44893 \dots^{16} + 32 \cdot 1.44893 \dots^{15} + 30 \cdot 1.44893 \dots^{14} + 28 \cdot 1.44893 \dots^{13} + 26 \cdot 1.44893 \dots^{12} + 24 \cdot 1.44893 \dots^{11} + 22 \cdot 1.44893 \dots^{10} + 20 \cdot 1.44893 \dots^{9} + 18 \cdot 1.44893 \dots^{8} + 16 \cdot 1.44893 \dots^{7} + 14 \cdot 1.44893 \dots^{6} + 12 \cdot 1.44893 \dots^{5} + 10 \cdot 1.44893 \dots^{4} + 8 \cdot 1.44893 \dots^{3} + 6 \cdot 1.44893 \dots^{2} + 4 \cdot 1.44893 \dots + 1 = 131710.17919 \dots

u_{21} = 1.36746 \dots

Δ u_{21} = ∣ 1.36746 \dots - 1.44893 \dots ∣ = 0.08146 \dots

Δ u_{21} = 0.08146 \dots

u_{22} = 1.28850 \dots : Δ u_{22} = 0.07896 \dots

f (u_{21}) = 2 \cdot 1.36746 \dots^{20} + 2 \cdot 1.36746 \dots^{19} + 2 \cdot 1.36746 \dots^{18} + 2 \cdot 1.36746 \dots^{17} + 2 \cdot 1.36746 \dots^{16} + 2 \cdot 1.36746 \dots^{15} + 2 \cdot 1.36746 \dots^{14} + 2 \cdot 1.36746 \dots^{13} + 2 \cdot 1.36746 \dots^{12} + 2 \cdot 1.36746 \dots^{11} + 2 \cdot 1.36746 \dots^{10} + 2 \cdot 1.36746 \dots^{9} + 2 \cdot 1.36746 \dots^{8} + 2 \cdot 1.36746 \dots^{7} + 2 \cdot 1.36746 \dots^{6} + 2 \cdot 1.36746 \dots^{5} + 2 \cdot 1.36746 \dots^{4} + 2 \cdot 1.36746 \dots^{3} + 2 \cdot 1.36746 \dots^{2} + 1.36746 \dots + 1 = 3883.34198 \dots

f^{^{'}} (u_{21}) = 40 \cdot 1.36746 \dots^{19} + 38 \cdot 1.36746 \dots^{18} + 36 \cdot 1.36746 \dots^{17} + 34 \cdot 1.36746 \dots^{16} + 32 \cdot 1.36746 \dots^{15} + 30 \cdot 1.36746 \dots^{14} + 28 \cdot 1.36746 \dots^{13} + 26 \cdot 1.36746 \dots^{12} + 24 \cdot 1.36746 \dots^{11} + 22 \cdot 1.36746 \dots^{10} + 20 \cdot 1.36746 \dots^{9} + 18 \cdot 1.36746 \dots^{8} + 16 \cdot 1.36746 \dots^{7} + 14 \cdot 1.36746 \dots^{6} + 12 \cdot 1.36746 \dots^{5} + 10 \cdot 1.36746 \dots^{4} + 8 \cdot 1.36746 \dots^{3} + 6 \cdot 1.36746 \dots^{2} + 4 \cdot 1.36746 \dots + 1 = 49180.53699 \dots

u_{22} = 1.28850 \dots

Δ u_{22} = ∣ 1.28850 \dots - 1.36746 \dots ∣ = 0.07896 \dots

Δ u_{22} = 0.07896 \dots

u_{23} = 1.21118 \dots : Δ u_{23} = 0.07732 \dots

f (u_{22}) = 2 \cdot 1.28850 \dots^{20} + 2 \cdot 1.28850 \dots^{19} + 2 \cdot 1.28850 \dots^{18} + 2 \cdot 1.28850 \dots^{17} + 2 \cdot 1.28850 \dots^{16} + 2 \cdot 1.28850 \dots^{15} + 2 \cdot 1.28850 \dots^{14} + 2 \cdot 1.28850 \dots^{13} + 2 \cdot 1.28850 \dots^{12} + 2 \cdot 1.28850 \dots^{11} + 2 \cdot 1.28850 \dots^{10} + 2 \cdot 1.28850 \dots^{9} + 2 \cdot 1.28850 \dots^{8} + 2 \cdot 1.28850 \dots^{7} + 2 \cdot 1.28850 \dots^{6} + 2 \cdot 1.28850 \dots^{5} + 2 \cdot 1.28850 \dots^{4} + 2 \cdot 1.28850 \dots^{3} + 2 \cdot 1.28850 \dots^{2} + 1.28850 \dots + 1 = 1412.13758 \dots

f^{^{'}} (u_{22}) = 40 \cdot 1.28850 \dots^{19} + 38 \cdot 1.28850 \dots^{18} + 36 \cdot 1.28850 \dots^{17} + 34 \cdot 1.28850 \dots^{16} + 32 \cdot 1.28850 \dots^{15} + 30 \cdot 1.28850 \dots^{14} + 28 \cdot 1.28850 \dots^{13} + 26 \cdot 1.28850 \dots^{12} + 24 \cdot 1.28850 \dots^{11} + 22 \cdot 1.28850 \dots^{10} + 20 \cdot 1.28850 \dots^{9} + 18 \cdot 1.28850 \dots^{8} + 16 \cdot 1.28850 \dots^{7} + 14 \cdot 1.28850 \dots^{6} + 12 \cdot 1.28850 \dots^{5} + 10 \cdot 1.28850 \dots^{4} + 8 \cdot 1.28850 \dots^{3} + 6 \cdot 1.28850 \dots^{2} + 4 \cdot 1.28850 \dots + 1 = 18261.62900 \dots

u_{23} = 1.21118 \dots

Δ u_{23} = ∣ 1.21118 \dots - 1.28850 \dots ∣ = 0.07732 \dots

Δ u_{23} = 0.07732 \dots

u_{24} = 1.13409 \dots : Δ u_{24} = 0.07708 \dots

f (u_{23}) = 2 \cdot 1.21118 \dots^{20} + 2 \cdot 1.21118 \dots^{19} + 2 \cdot 1.21118 \dots^{18} + 2 \cdot 1.21118 \dots^{17} + 2 \cdot 1.21118 \dots^{16} + 2 \cdot 1.21118 \dots^{15} + 2 \cdot 1.21118 \dots^{14} + 2 \cdot 1.21118 \dots^{13} + 2 \cdot 1.21118 \dots^{12} + 2 \cdot 1.21118 \dots^{11} + 2 \cdot 1.21118 \dots^{10} + 2 \cdot 1.21118 \dots^{9} + 2 \cdot 1.21118 \dots^{8} + 2 \cdot 1.21118 \dots^{7} + 2 \cdot 1.21118 \dots^{6} + 2 \cdot 1.21118 \dots^{5} + 2 \cdot 1.21118 \dots^{4} + 2 \cdot 1.21118 \dots^{3} + 2 \cdot 1.21118 \dots^{2} + 1.21118 \dots + 1 = 517.69016 \dots

f^{^{'}} (u_{23}) = 40 \cdot 1.21118 \dots^{19} + 38 \cdot 1.21118 \dots^{18} + 36 \cdot 1.21118 \dots^{17} + 34 \cdot 1.21118 \dots^{16} + 32 \cdot 1.21118 \dots^{15} + 30 \cdot 1.21118 \dots^{14} + 28 \cdot 1.21118 \dots^{13} + 26 \cdot 1.21118 \dots^{12} + 24 \cdot 1.21118 \dots^{11} + 22 \cdot 1.21118 \dots^{10} + 20 \cdot 1.21118 \dots^{9} + 18 \cdot 1.21118 \dots^{8} + 16 \cdot 1.21118 \dots^{7} + 14 \cdot 1.21118 \dots^{6} + 12 \cdot 1.21118 \dots^{5} + 10 \cdot 1.21118 \dots^{4} + 8 \cdot 1.21118 \dots^{3} + 6 \cdot 1.21118 \dots^{2} + 4 \cdot 1.21118 \dots + 1 = 6715.60947 \dots

u_{24} = 1.13409 \dots

Δ u_{24} = ∣ 1.13409 \dots - 1.21118 \dots ∣ = 0.07708 \dots

Δ u_{24} = 0.07708 \dots

u_{25} = 1.05480 \dots : Δ u_{25} = 0.07929 \dots

f (u_{24}) = 2 \cdot 1.13409 \dots^{20} + 2 \cdot 1.13409 \dots^{19} + 2 \cdot 1.13409 \dots^{18} + 2 \cdot 1.13409 \dots^{17} + 2 \cdot 1.13409 \dots^{16} + 2 \cdot 1.13409 \dots^{15} + 2 \cdot 1.13409 \dots^{14} + 2 \cdot 1.13409 \dots^{13} + 2 \cdot 1.13409 \dots^{12} + 2 \cdot 1.13409 \dots^{11} + 2 \cdot 1.13409 \dots^{10} + 2 \cdot 1.13409 \dots^{9} + 2 \cdot 1.13409 \dots^{8} + 2 \cdot 1.13409 \dots^{7} + 2 \cdot 1.13409 \dots^{6} + 2 \cdot 1.13409 \dots^{5} + 2 \cdot 1.13409 \dots^{4} + 2 \cdot 1.13409 \dots^{3} + 2 \cdot 1.13409 \dots^{2} + 1.13409 \dots + 1 = 192.47985 \dots

f^{^{'}} (u_{24}) = 40 \cdot 1.13409 \dots^{19} + 38 \cdot 1.13409 \dots^{18} + 36 \cdot 1.13409 \dots^{17} + 34 \cdot 1.13409 \dots^{16} + 32 \cdot 1.13409 \dots^{15} + 30 \cdot 1.13409 \dots^{14} + 28 \cdot 1.13409 \dots^{13} + 26 \cdot 1.13409 \dots^{12} + 24 \cdot 1.13409 \dots^{11} + 22 \cdot 1.13409 \dots^{10} + 20 \cdot 1.13409 \dots^{9} + 18 \cdot 1.13409 \dots^{8} + 16 \cdot 1.13409 \dots^{7} + 14 \cdot 1.13409 \dots^{6} + 12 \cdot 1.13409 \dots^{5} + 10 \cdot 1.13409 \dots^{4} + 8 \cdot 1.13409 \dots^{3} + 6 \cdot 1.13409 \dots^{2} + 4 \cdot 1.13409 \dots + 1 = 2427.51025 \dots

u_{25} = 1.05480 \dots

Δ u_{25} = ∣ 1.05480 \dots - 1.13409 \dots ∣ = 0.07929 \dots

Δ u_{25} = 0.07929 \dots

u_{26} = 0.96859 \dots : Δ u_{26} = 0.08620 \dots

f (u_{25}) = 2 \cdot 1.05480 \dots^{20} + 2 \cdot 1.05480 \dots^{19} + 2 \cdot 1.05480 \dots^{18} + 2 \cdot 1.05480 \dots^{17} + 2 \cdot 1.05480 \dots^{16} + 2 \cdot 1.05480 \dots^{15} + 2 \cdot 1.05480 \dots^{14} + 2 \cdot 1.05480 \dots^{13} + 2 \cdot 1.05480 \dots^{12} + 2 \cdot 1.05480 \dots^{11} + 2 \cdot 1.05480 \dots^{10} + 2 \cdot 1.05480 \dots^{9} + 2 \cdot 1.05480 \dots^{8} + 2 \cdot 1.05480 \dots^{7} + 2 \cdot 1.05480 \dots^{6} + 2 \cdot 1.05480 \dots^{5} + 2 \cdot 1.05480 \dots^{4} + 2 \cdot 1.05480 \dots^{3} + 2 \cdot 1.05480 \dots^{2} + 1.05480 \dots + 1 = 73.34809 \dots

f^{^{'}} (u_{25}) = 40 \cdot 1.05480 \dots^{19} + 38 \cdot 1.05480 \dots^{18} + 36 \cdot 1.05480 \dots^{17} + 34 \cdot 1.05480 \dots^{16} + 32 \cdot 1.05480 \dots^{15} + 30 \cdot 1.05480 \dots^{14} + 28 \cdot 1.05480 \dots^{13} + 26 \cdot 1.05480 \dots^{12} + 24 \cdot 1.05480 \dots^{11} + 22 \cdot 1.05480 \dots^{10} + 20 \cdot 1.05480 \dots^{9} + 18 \cdot 1.05480 \dots^{8} + 16 \cdot 1.05480 \dots^{7} + 14 \cdot 1.05480 \dots^{6} + 12 \cdot 1.05480 \dots^{5} + 10 \cdot 1.05480 \dots^{4} + 8 \cdot 1.05480 \dots^{3} + 6 \cdot 1.05480 \dots^{2} + 4 \cdot 1.05480 \dots + 1 = 850.85072 \dots

u_{26} = 0.96859 \dots

Δ u_{26} = ∣ 0.96859 \dots - 1.05480 \dots ∣ = 0.08620 \dots

Δ u_{26} = 0.08620 \dots

Não se pode encontrar solução

A solução é

Sem solu \overset{c}{\c} \tilde{a} o para u \in R

As soluções são

u = 0, u = 1

Substituir na equação

u = sin (x)

sin (x) = 0, sin (x) = 1

sin (x) = 0, sin (x) = 1

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

Soluções gerais para

sin (x) = 0

sin (x)

tabela de periodicidade com ciclo de

2 πn

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Resolver

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = 1

Soluções gerais para

sin (x) = 1

sin (x)

tabela de periodicidade com ciclo de

2 πn

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

Combinar toda as soluções

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

Gráfico

Exemplos populares

(1+tan^2(x))/(1+sec(x))=sec(x)

\frac{1 + tan ^{2} ( x )}{1 + sec ( x )} = sec (x)

-sin^2(x)+2cos(x)-2=0

- sin^{2} (x) + 2 cos (x) - 2 = 0

sin(5x-1)= 4/5

sin (5 x - 1) = \frac{4}{5}

sin^2(x)= 1/36

sin^{2} (x) = \frac{1}{36}

tan(x)=31

tan (x) = 31