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受欢迎的三角函数 >

cot(2x-3)-1=0

解答

cot (2 x - 3) - 1 = 0

解答

x = \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

+1

度数

x = 108.44366 \dots^{\circ} + 9 0^{\circ} n

求解步骤

cot (2 x - 3) - 1 = 0

将

1

到右边

cot (2 x - 3) - 1 = 0

两边加上

1

cot (2 x - 3) - 1 + 1 = 0 + 1

化简

cot (2 x - 3) = 1

cot (2 x - 3) = 1

cot (2 x - 3) = 1

的通解

cot (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

2 x - 3 = \frac{π}{4} + πn

2 x - 3 = \frac{π}{4} + πn

解

2 x - 3 = \frac{π}{4} + πn : x = \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

2 x - 3 = \frac{π}{4} + πn

将

3

到右边

2 x - 3 = \frac{π}{4} + πn

两边加上

3

2 x - 3 + 3 = \frac{π}{4} + πn + 3

化简

2 x = \frac{π}{4} + πn + 3

2 x = \frac{π}{4} + πn + 3

两边除以

2

2 x = \frac{π}{4} + πn + 3

两边除以

2

\frac{2 x}{2} = \frac{\frac{π}{4}}{2} + \frac{πn}{2} + \frac{3}{2}

化简

\frac{2 x}{2} = \frac{\frac{π}{4}}{2} + \frac{πn}{2} + \frac{3}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{π}{4}}{2} + \frac{πn}{2} + \frac{3}{2} : \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

\frac{\frac{π}{4}}{2} + \frac{πn}{2} + \frac{3}{2}

对同类项分组

= \frac{3}{2} + \frac{πn}{2} + \frac{\frac{π}{4}}{2}

\frac{\frac{π}{4}}{2} = \frac{π}{8}

\frac{\frac{π}{4}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{4 \cdot 2}

数字相乘:

4 \cdot 2 = 8

= \frac{π}{8}

= \frac{3}{2} + \frac{πn}{2} + \frac{π}{8}

对同类项分组

= \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

x = \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

x = \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

x = \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

x = \frac{3}{2} + \frac{π}{8} + \frac{πn}{2}

作图

流行的例子

4sin^{32}(x)-3cos^2(x)=0

4 sin^{32} (x) - 3 cos^{2} (x) = 0

4tan^2(x)+15sec(x)=0

4 tan^{2} (x) + 15 sec (x) = 0

sin^4(x)+cos^4(x)=cos^4(x)

sin^{4} (x) + cos^{4} (x) = cos^{4} (x)

cot (x) = \frac{40}{32}

tan (a) = \frac{3}{8}