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人気のある三角関数 >

solvefor y,7y=sin^2(x)-4sin(x)+3

解

解く

y, 7 y = sin^{2} (x) - 4 sin (x) + 3

解

y = \frac{sin ^{2} ( x ) - 4 sin ( x ) + 3}{7}

解答ステップ

7 y = sin^{2} (x) - 4 sin (x) + 3

以下で両辺を割る

7

7 y = sin^{2} (x) - 4 sin (x) + 3

以下で両辺を割る

7

\frac{7 y}{7} = \frac{sin ^{2} ( x )}{7} - \frac{4 sin ( x )}{7} + \frac{3}{7}

簡素化

\frac{7 y}{7} = \frac{sin ^{2} ( x )}{7} - \frac{4 sin ( x )}{7} + \frac{3}{7}

簡素化

\frac{7 y}{7} : y

\frac{7 y}{7}

数を割る:

\frac{7}{7} = 1

= y

簡素化

\frac{sin ^{2} ( x )}{7} - \frac{4 sin ( x )}{7} + \frac{3}{7} : \frac{sin ^{2} ( x ) - 4 sin ( x ) + 3}{7}

\frac{sin ^{2} ( x )}{7} - \frac{4 sin ( x )}{7} + \frac{3}{7}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ^{2} ( x ) - 4 sin ( x ) + 3}{7}

y = \frac{sin ^{2} ( x ) - 4 sin ( x ) + 3}{7}

y = \frac{sin ^{2} ( x ) - 4 sin ( x ) + 3}{7}

y = \frac{sin ^{2} ( x ) - 4 sin ( x ) + 3}{7}

グラフ

人気の例

tan(11)= x/(12)

tan (1 1^{\circ}) = \frac{x}{12}

solvefor c,cos(x)-sin(x)+3sin^2(x)-1=0

so l v e f or c, cos (x) - sin (x) + 3 sin^{2} (x) - 1 = 0

solvefor c,sin(x)+cos(x)=cos^2(x)

so l v e f or c, sin (x) + cos (x) = cos^{2} (x)

solvefor a,sin(0)= a/h

so l v e f or a, sin (0) = \frac{a}{h}

solvefor c,1-sin^2(x)=4cos(x)-4sin(x)

so l v e f or c, 1 - sin^{2} (x) = 4 cos (x) - 4 sin (x)