A person places 133 in an investment account earning an annual rate of 5.8%, compounded continuously. Using the formula V, equals, P, e, start superscript, r, t, end superscriptV=Pe^{rt}, where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 9 years

Soluzione

A p erso n pl a ces 133 in an in v es t m e n t a cco u n t e a r nin g an ann u a l r a t e o f 5.8%, co m p o u n d e d co n t in u o u s l y . U s in g t h e f or m u l a V, e q u a l s, P, e, s t a r t s u p erscr i pt, r, t, e n d s u p erscr i pt V = P e^{r t}, w h ere V i s t h e v a l u e o f t h e a cco u n t in t ye a rs, P i s t h e p r in c i p a l ini t ia ll y in v es t e d, e i s t h e ba se o f a na t u r a l l o g a r i t hm, an d r i s t h e r a t e o f in t eres t, d e t er min e t h e am o u n t o f m o n ey, t o t h e n e a res t ce n t, in t h e a cco u n t a f t er 9 ye a rs

Amount : 224.16

Fasi della soluzione

Translate the problem into an equation:

A = 133 e^{0.058 \cdot 9}

133 e^{0.058 \cdot 9} = 224.15754 \dots

Arrotondare all' hundredth più vicino:

224.16

Amount : 224.16