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Phổ biến Word Problems >

The sum of the ages of a father and son is 56. Four years ago the father was 3 times as old as the son. Find the present age of each.

Lời Giải

T h e s u m o f t h e a g es o f a f a t h er an d so n i s 56. F o u r ye a rs a g o t h e f a t h er w a s 3 t im es a s o l d a s t h e so n . F in d t h e p rese n t a g e o f e a c h .

Lời Giải

Father^{'} s age is : 40

Boy^{'} s age is : 16

Các bước giải pháp

Translate the problem into an equation:

x - 4 = 3 (56 - x - 4)

Giải

x, x - 4 = 3 (56 - x - 4) : x = 40

Tìm age

Father^{'} s age is : 40

Boy^{'} s age is : 16

Ví dụ phổ biến

rút gọn Nine years ago, Jareth was five times as old as Dave. Now, he is only three times as old as Dave. Find their present ages.Melvin is 18 years older than his daughter, Melly. Eight years ago, he was 7 times as old as his daughter. Find the present age of Melly.Andrei is 6 years older than his sister Andrea. After 10 years, the sum of their ages will be 50. How old is Andrea?Carmen is 9 years older than David. Seven years ago, the sum of their ages was 25. How old are they now?Carmen is 5 years older than David. A year ago, the sum of their ages was 13. How old are they now?