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Popular Word Problems >

Find two consecutive odd integers such that 1/3 the smaller plus twice the larger equals 7 more than the sum of the two numbers

Solución

F in d tw o co n sec u t i v e o dd in t e g ers s u c h t ha t 1/3 t h e s ma ll er pl u s tw i ce t h e l a r g er e q u a l s 7 m ore t han t h e s u m o f t h e tw o n u mb ers

Solución

The numbers : 15, 17

Pasos de solución

Represent the numbers with

x

:

First number : x

Consecutive number : x + 2

A.T.Q.:

\frac{1}{3} x + 2 (x + 2) = 7 + x + x + 2

Resolver

\frac{1}{3} x + 2 (x + 2) = 7 + x + x + 2 : x = 15

x + 2 = 15 + 2 = 17

The numbers : 15, 17

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