vereinfachen (27z^{2/3})^{1/3}

Lösung

vereinfachen

(27 z^{\frac{2}{3}})^{\frac{1}{3}}

3 z^{\frac{2}{9}}

Schritte zur Lösung

(27 z^{\frac{2}{3}})^{\frac{1}{3}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(27 z^{\frac{2}{3}})^{\frac{1}{3}} = 2 7^{\frac{1}{3}} (z^{\frac{2}{3}})^{\frac{1}{3}}

= 2 7^{\frac{1}{3}} (z^{\frac{2}{3}})^{\frac{1}{3}}

2 7^{\frac{1}{3}} = 3

= 3 (z^{\frac{2}{3}})^{\frac{1}{3}}

Wende Exponentenregel an:

(a^{b})^{c} = a^{b c},

angenommen

a \geq 0

(z^{\frac{2}{3}})^{\frac{1}{3}} = z^{\frac{2}{3} \cdot \frac{1}{3}}

= 3 z^{\frac{2}{3} \cdot \frac{1}{3}}

\frac{2}{3} \cdot \frac{1}{3} = \frac{2}{9}

= 3 z^{\frac{2}{9}}

(16 + 2 x) (22 + 2 x) = 1512

f a c t or 25 x^{2} - 90 x + 81

∣ - 10 r ∣ < 20

s im pl i f y p^{- 2}

e x p an d (2 x + 5)^{2}