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受欢迎的代数 >

-4.9t^2+11t+500=0

解答

- 4.9 t^{2} + 11 t + 500 = 0

解答

t = - \frac{5 ( 9921 - 11 )}{49}, t = \frac{5 ( 11 + 9921 )}{49}

+1

十进制

t = - 9.04124 \dots, t = 11.28614 \dots

求解步骤

- 4.9 t^{2} + 11 t + 500 = 0

在两边乘以

10

- 49 t^{2} + 110 t + 5000 = 0

使用求根公式求解

t_{1, 2} = \frac{- 110 \pm 11 0 ^{2} - 4 ( - 49 ) \cdot 5000}{2 ( - 49 )}

11 0^{2} - 4 (- 49) \cdot 5000 = 109921

t_{1, 2} = \frac{- 110 \pm 10 9921}{2 ( - 49 )}

将解分隔开

t_{1} = \frac{- 110 + 10 9921}{2 ( - 49 )}, t_{2} = \frac{- 110 - 10 9921}{2 ( - 49 )}

t = \frac{- 110 + 10 9921}{2 ( - 49 )} : - \frac{5 ( 9921 - 11 )}{49}

t = \frac{- 110 - 10 9921}{2 ( - 49 )} : \frac{5 ( 11 + 9921 )}{49}

二次方程组的解是:

t = - \frac{5 ( 9921 - 11 )}{49}, t = \frac{5 ( 11 + 9921 )}{49}

作图

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