18x^2-(9x+2)(2x-1)=1

解答

18 x^{2} - (9 x + 2) (2 x - 1) = 1

x = - \frac{1}{5}

十进制

x = - 0.2

求解步骤

18 x^{2} - (9 x + 2) (2 x - 1) = 1

乘开

- (9 x + 2) (2 x - 1) : - 18 x^{2} + 5 x + 2

18 x^{2} - 18 x^{2} + 5 x + 2 = 1

s im pl i f y \frac{28 - 7 k ^{2}}{k ^{2} - 4}

3 x - 2 = 0

x - \frac{x}{6} = 1

f a c t or 13 x y^{4} + 65 x^{3} y^{3}

s im pl i f y \frac{25}{9}