(2x+1)^3=125

Lösung

(2 x + 1)^{3} = 125

x = 2, x = - \frac{7}{4} + i \frac{5 3}{4}, x = - \frac{7}{4} - i \frac{5 3}{4}

Schritte zur Lösung

(2 x + 1)^{3} = 125

Für

g^{3} (x) = f (a)

sind die Lösungen

g (x) = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

Löse

2 x + 1 = 3125 : x = 2

Löse

2 x + 1 = 3125 \frac{- 1 + 3 i}{2} : x = - \frac{7}{4} + i \frac{5 3}{4}

Löse

2 x + 1 = 3125 \frac{- 1 - 3 i}{2} : x = - \frac{7}{4} - i \frac{5 3}{4}

Die Lösungen sind

x = 2, x = - \frac{7}{4} + i \frac{5 3}{4}, x = - \frac{7}{4} - i \frac{5 3}{4}

z^{4} - 25 = 0

\frac{( x - 4 )}{5} = x^{23} - 5

x^{3} - 6 x^{2} + 3 = 0

2 y^{3} = 5 + 4 y

so l v e f or a, a^{5} - b^{4} = 0