erweitern (3Q(80000-Q))/(2000)

Lösung

erweitern

\frac{3 Q ( 80000 - Q )}{2000}

- \frac{3 Q ^{2}}{2000} + 120 Q

Schritte zur Lösung

\frac{3 Q ( 80000 - Q )}{2000}

Multipliziere aus

3 Q (80000 - Q) : 240000 Q - 3 Q^{2}

= \frac{240000 Q - 3 Q ^{2}}{2000}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{240000 Q - 3 Q ^{2}}{2000} = \frac{240000 Q}{2000} - \frac{3 Q ^{2}}{2000}

= \frac{240000 Q}{2000} - \frac{3 Q ^{2}}{2000}

Teile die Zahlen:

\frac{240000}{2000} = 120

= 120 Q - \frac{3 Q ^{2}}{2000}

Rewrite in standard form

= - \frac{3 Q ^{2}}{2000} + 120 Q

e x p an d x^{3} (x^{3} + 2 x + 3)^{2} d x

e x p an d e^{2 x} (1 + e^{2 x})^{3} d x

e x p an d (- 3) (4 x - 5 y = 3)

e x p an d - 3 ((- 2, 1, 1) - (4, 3, 5))

e x p an d \frac{( 4 + x ) ^{3}}{8}