-1(x)=(x^2-6x+3)/(x+4)

解

- 1 (x) = \frac{x ^{2} - 6 x + 3}{x + 4}

x = \frac{1}{2} + i \frac{5}{2}, x = \frac{1}{2} - i \frac{5}{2}

解答ステップ

- 1 \cdot (x) = \frac{x ^{2} - 6 x + 3}{x + 4}

以下で両辺を乗じる:

x + 4

- x (x + 4) = x^{2} - 6 x + 3

解く

- x (x + 4) = x^{2} - 6 x + 3 : x = \frac{1}{2} + i \frac{5}{2}, x = \frac{1}{2} - i \frac{5}{2}

x = \frac{1}{2} + i \frac{5}{2}, x = \frac{1}{2} - i \frac{5}{2}