(1/2)^{x+2}=16^{-x}

Lösung

(\frac{1}{2})^{x + 2} = 1 6^{- x}

x = \frac{2}{3}

Dezimale

x = 0.66666 \dots

Schritte zur Lösung

(\frac{1}{2})^{x + 2} = 1 6^{- x}

Wende Exponentenregel an

- (x + 2) = - 4 x

Löse

- (x + 2) = - 4 x : x = \frac{2}{3}

x = \frac{2}{3}

e^{x} = x + 2

\frac{7 ^{7}}{7 ^{3}} = 7^{x}

5^{- x} = 125

3 = e^{x}

2^{x} = 65536