4^{x+1}=16^{x-1}

Lösung

4^{x + 1} = 1 6^{x - 1}

x = 3

Schritte zur Lösung

4^{x + 1} = 1 6^{x - 1}

Wende Exponentenregel an

x + 1 = 2 (x - 1)

Löse

x + 1 = 2 (x - 1) : x = 3

x = 3

(3)^{x} = 2 7^{x - 1}

4^{3 x} = 1 6^{2 - x}

4^{x} = 2^{\frac{8}{x}}

5^{x} = \frac{2}{5}

so l v e f or x, x e^{y} + y e^{x} = 2