e^{x+1}=1

Lösung

e^{x + 1} = 1

x = - 1

Schritte zur Lösung

e^{x + 1} = 1

Wende Exponentenregel an

x + 1 = ln (1)

Löse

x + 1 = ln (1) : x = - 1

x = - 1

2 7^{2 x - 1} = 9^{x - 2}

so l v e f or n, (ab)^{n} = a^{n} b^{n}

4^{x + 1} - 2^{5 + x} - 2^{x} + 2^{3} = 0

4^{x} = 532

- 3 e^{9 x - 1} + 6 = - 58