2^{x+3}=4^{x-2}

Lösung

2^{x + 3} = 4^{x - 2}

x = 7

Schritte zur Lösung

2^{x + 3} = 4^{x - 2}

Wende Exponentenregel an

x + 3 = 2 (x - 2)

Löse

x + 3 = 2 (x - 2) : x = 7

x = 7

5^{3 r - 5} = 5^{2}

0 = e^{x^{2}}

2^{2 x} - 2 \cdot 2^{x} - 8 = 0

3 e^{x} + 2 = 5

9^{6 x} = 1 1^{x - 3}