7^{2+x}=98

Lösung

7^{2 + x} = 98

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

Dezimale

x = 0.35620 \dots

Schritte zur Lösung

7^{2 + x} = 98

Wende Exponentenregel an

(2 + x) ln (7) = ln (98)

Löse

(2 + x) ln (7) = ln (98) : x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

2^{x^{3}} = 12 8^{x}

6^{2 x - 1} + 180 = 6^{2 x}

3^{x + 2} = 3^{2 x - 5}

2 (2^{2 x}) + 4 = 9 (2^{x})

\frac{40}{1 + e ^{- x}} = 2