2^{x-2}=5

Lösung

2^{x - 2} = 5

x = \frac{ln ( 5 )}{ln ( 2 )} + 2

Dezimale

x = 4.32192 \dots

Schritte zur Lösung

2^{x - 2} = 5

Wende Exponentenregel an

(x - 2) ln (2) = ln (5)

Löse

(x - 2) ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )} + 2

x = \frac{ln ( 5 )}{ln ( 2 )} + 2

5^{100} - 5^{99} = 4 \cdot 5^{x}

2 = c e^{- t} + \frac{1}{2 e ^{t}}

8^{5 x} = 1 6^{3 x + 4}

e^{4 x} - 5 e^{2 x} + 4 = 0

3^{x} - 9^{2 x} = 2 7^{3 x}