y^9× (y^2)^{-1}y=-2

Lösung

y^{9} \cdot (y^{2})^{- 1} y = - 2

y = \frac{1}{2 ^{\frac{5}{8}} 2 - 1} + \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{4}} \cdot \frac{2 - 1}{2 ^{\frac{5}{8}}}} - \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{8}} 1 + 2} + \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 1 + 2} - \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 1 + 2} + \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{4}} \cdot \frac{1 + 2}{2 ^{\frac{5}{8}}}} - \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{8}} 2 - 1} + \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 2 - 1} - \frac{2 - 1}{2 ^{\frac{5}{8}}} i

Schritte zur Lösung

y^{9} (y^{2})^{- 1} y = - 2

Fasse zusammen

y^{8} = - 2

Löse

y^{8} = - 2 : y = \frac{1}{2 ^{\frac{5}{8}} 2 - 1} + \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{4}} \cdot \frac{2 - 1}{2 ^{\frac{5}{8}}}} - \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{8}} 1 + 2} + \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 1 + 2} - \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 1 + 2} + \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{4}} \cdot \frac{1 + 2}{2 ^{\frac{5}{8}}}} - \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{8}} 2 - 1} + \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 2 - 1} - \frac{2 - 1}{2 ^{\frac{5}{8}}} i

y = \frac{1}{2 ^{\frac{5}{8}} 2 - 1} + \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{4}} \cdot \frac{2 - 1}{2 ^{\frac{5}{8}}}} - \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{8}} 1 + 2} + \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 1 + 2} - \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 1 + 2} + \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{4}} \cdot \frac{1 + 2}{2 ^{\frac{5}{8}}}} - \frac{1 + 2}{2 ^{\frac{5}{8}}} i, y = - \frac{1}{2 ^{\frac{5}{8}} 2 - 1} + \frac{2 - 1}{2 ^{\frac{5}{8}}} i, y = \frac{1}{2 ^{\frac{5}{8}} 2 - 1} - \frac{2 - 1}{2 ^{\frac{5}{8}}} i

\frac{60}{( - x )} = 4

\frac{x}{4} = \frac{9}{4 x}

\frac{8 x}{3 x + 5} + \frac{5 x - 1}{x + 1} = 3

so l v e f or a, \frac{1}{a} + \frac{1}{b} = \frac{1}{a + b}

- 4 x + \frac{4}{x} = 0