x^2+5x-14=0

解答

x^{2} + 5 x - 14 = 0

x = 2, x = - 7

求解步骤

x^{2} + 5 x - 14 = 0

使用求根公式求解

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 5 + 9}{2 \cdot 1}, x_{2} = \frac{- 5 - 9}{2 \cdot 1}

x = \frac{- 5 + 9}{2 \cdot 1} : 2

x = \frac{- 5 - 9}{2 \cdot 1} : - 7

二次方程组的解是:

x = 2, x = - 7

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