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Beliebt Rechnen >

(x-1)y^'+(2x+1)y=0

Lösung

(x - 1) y^{^{'}} + (2 x + 1) y = 0

Lösung

y = \frac{e ^{- 2 x + 2 + c_{1}}}{x ^{3} - 3 x ^{2} + 3 x - 1}

Schritte zur Lösung

(x - 1) y^{'} (x) + (2 x + 1) y = 0

Solve separable ODE:

y = \frac{e ^{- 2 x + 2 + c_{1}}}{x ^{3} - 3 x ^{2} + 3 x - 1}

y = \frac{e ^{- 2 x + 2 + c_{1}}}{x ^{3} - 3 x ^{2} + 3 x - 1}

Graph

Beliebte Beispiele

d/(ds)(ln((s-1)/(s^2+2s+5)))

\frac{d}{d s} (ln (\frac{s - 1}{s ^{2} + 2 s + 5}))

tangent f(x)=x^2-x+2,\at x=-1

t an g e n t f (x) = x^{2} - x + 2, at x = - 1

9y^{''}+18y^'+17y=0

9 y^{^{''}} + 18 y^{^{'}} + 17 y = 0

sum from n=1 to infinity of (2n)/(5n+1)

n = 1 \sum \infty \frac{2 n}{5 n + 1}

(\partial)/(\partial y)((12x)/(x+y))

\frac{\partial}{\partial y} (\frac{12 x}{x + y})