y^'=y^2sin(t)

Lösung

y^{^{'}} = y^{2} sin (t)

y = - \frac{1}{- cos ( t ) + c _{1}}

Schritte zur Lösung

y^{'} (t) = y^{2} sin (t)

Solve separable ODE:

y = - \frac{1}{- cos ( t ) + c _{1}}

y = - \frac{1}{- cos ( t ) + c _{1}}

x \to 0 lim (x csc (4 x))

l a pl a ce t r an s f or m 11

\frac{d}{d x} (\frac{2 x}{4 x - 1})

d er i v a t i v e y, (9 x e^{- \frac{1}{y ^{3}}} - 20 x^{3})

\frac{d}{d x} ((3 - 2 x)^{5})