(\partial)/(\partial x)(x^3-6xy+y^3-2)

Lösung

\frac{\partial}{\partial x} (x^{3} - 6 x y + y^{3} - 2)

3 x^{2} - 6 y

Schritte zur Lösung

\frac{\partial}{\partial x} (x^{3} - 6 x y + y^{3} - 2)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (6 x y) + \frac{\partial}{\partial x} (y^{3}) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (6 x y) = 6 y

\frac{\partial}{\partial x} (y^{3}) = 0

\frac{\partial}{\partial x} (2) = 0

= 3 x^{2} - 6 y + 0 - 0

Vereinfache

= 3 x^{2} - 6 y

\frac{d}{d t} (+ 6 t)

\int_{4}^{10} \frac{1}{36 + ( x - 4 ) ^{2}} d x

\frac{d}{d x} (6 x - 6 e^{x})

\frac{d}{d x} (9 + x)

in v erse l a pl a ce \frac{1}{9 s ^{2} + 1}