taylor 4/x ,1

Lösung

taylor

\frac{4}{x}, 1

4 - 4 (x - 1) + 4 (x - 1)^{2} - 4 (x - 1)^{3} + 4 (x - 1)^{4} + \dots

Schritte zur Lösung

Apply the Taylor Formula

= 4 + \frac{\frac{d}{d x} ( \frac{4}{x} ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{4}{x} ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{4}{x} ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 4 + \frac{- 4}{1 !} (x - 1) + \frac{8}{2 !} (x - 1)^{2} + \frac{- 24}{3 !} (x - 1)^{3} + \frac{96}{4 !} (x - 1)^{4} + \dots

Fasse zusammen

= 4 - 4 (x - 1) + 4 (x - 1)^{2} - 4 (x - 1)^{3} + 4 (x - 1)^{4} + \dots

\frac{d}{d x} ((3 x^{2} + 3) (2 x^{2} + 1))

d er i v a t i v e 2 x^{2} - 2 x + 4

y^{^{'''}} - 9 y^{^{''}} + 18 y^{^{'}} = e^{e^{- 3 x}}

\frac{\partial}{\partial t} (\frac{r}{t})

d er i v a t i v e \frac{( m v ^{2} )}{r}