x^'=-0.0002sqrt(x)

Lösung

x^{^{'}} = - 0.0002 x

x = \frac{0.00000004 t ^{2}}{4} - \frac{0.0004 c _{1} t}{4} + \frac{c _{1}^{2}}{4}

Schritte zur Lösung

x^{'} (t) = - 0.0002 x

Solve separable ODE:

x = \frac{0.00000004 t ^{2}}{4} - \frac{0.0004 c _{1} t}{4} + \frac{c _{1}^{2}}{4}

x = \frac{0.00000004 t ^{2}}{4} - \frac{0.0004 c _{1} t}{4} + \frac{c _{1}^{2}}{4}

x \to 0 lim (\frac{3 x}{2 x ^{2} + x})

\int (e^{4 x} - 4)^{\frac{1}{5}} \cdot 8 e^{4 x} d x

d er i v a t i v e \frac{2 x}{1 - cot ( x )}

x \to 0 lim (\frac{1}{x + \frac{1}{x}})

in v erse l a pl a ce \frac{8 s}{3 ( s ^{2} - 16 ) ^{2}}