3y+x^4y^'=2xy

Lösung

3 y + x^{4} y^{^{'}} = 2 x y

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

Schritte zur Lösung

3 y + x^{4} y^{'} (x) = 2 x y

Solve separable ODE:

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

s l o p e (2, 2), (- 2, - 2)

x \to \infty lim (- 3^{x})

\int \frac{- 6 x ^{2}}{3 3 - 4 x ^{3}} d x

\int \frac{x ^{2} + 1}{x ( x ^{2} + 3 )} d x

d er i v a t i v e \frac{1}{x} cos (x)