y^'=sin(x-y)

解答

y^{^{'}} = sin (x - y)

y = - \frac{π}{2} - 2 πn + x, y = - 2 arctan (\frac{- 2 + c _{1} + x}{c _{1} + x}) - 2 πn + x

求解步骤

y^{'} (x) = sin (x - y)

使用替代法求解:

y = - \frac{π}{2} - 2 πn + x, y = - 2 arctan (\frac{- 2 + c _{1} + x}{c _{1} + x}) - 2 πn + x

y = - \frac{π}{2} - 2 πn + x, y = - 2 arctan (\frac{- 2 + c _{1} + x}{c _{1} + x}) - 2 πn + x