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Beliebt Rechnen >

inverselaplace (0.001s)/(s^2+4)

Lösung

inverse laplace transformation

\frac{0.001 s}{s ^{2} + 4}

Lösung

0.001 cos (2 t)

Schritte zur Lösung

L^{- 1} {\frac{0.001 s}{s ^{2} + 4}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {s F (s)} = \frac{d}{d t} f (t) + f (0)

Für

\frac{0.001 s}{s ^{2} + 4} : F (s) = \frac{0.001}{s ^{2} + 4}

= \frac{d}{d t} (L^{- 1} {\frac{0.001}{s ^{2} + 4}}) + L^{- 1} {\frac{0.001}{s ^{2} + 4}} (0)

L^{- 1} {\frac{0.001}{s ^{2} + 4}} : \frac{0.001}{2} sin (2 t)

\frac{d}{d t} (\frac{0.001}{2} sin (2 t)) = 0.001 cos (2 t)

Evaluiere

\frac{0.001}{2} sin (2 t)

am Punkt

0 = 0

= 0.001 cos (2 t)

Beliebte Beispiele

integral of (13x-6)/(x(3x-2))

sum from n=1 to infinity of ((1^n))/n

derivative of (2xdx)

integral of (ln(y))/y

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