(\partial)/(\partial y)(y^2-2xy+6x)

Lösung

\frac{\partial}{\partial y} (y^{2} - 2 x y + 6 x)

2 y - 2 x

Schritte zur Lösung

\frac{\partial}{\partial y} (y^{2} - 2 x y + 6 x)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) - \frac{\partial}{\partial y} (2 x y) + \frac{\partial}{\partial y} (6 x)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (6 x) = 0

= 2 y - 2 x + 0

Vereinfache

= 2 y - 2 x

\int_{0}^{1} \frac{x}{e ^{x^{2}}} d x

\frac{\partial}{\partial y} (\frac{a x}{y ^{2}})

\int \frac{1}{cos ( 8 x )} d x

\int_{0}^{2} 6 x (2 - x) d x

d er i v a t i v e (2 x - 3) e^{2 - x}