limit as h approaches 0 of (2x+h)-2x

Lösung

h \to 0 lim ((2 x + h) - 2 x)

0

Schritte zur Lösung

h \to 0 lim (2 x + h - 2 x)

Setze den Wert

h = 0

ein

= 2 x + 0 - 2 x

Vereinfache

= 0

d er i v a t i v e cos (\frac{1 - e ^{4 x}}{1 + e ^{4 x}})

y^{^{'}} = x^{\frac{2}{3}}

\int_{1}^{e^{4}} \frac{ln ( x )}{x ^{2}} d x

\frac{\partial}{\partial x} (5 (y^{2} - x^{2}) ln (x + y))

t^{2} y^{^{''}} - 2 y = 0