y^'=-0.02(y-20)

Lösung

y^{^{'}} = - 0.02 (y - 20)

y = e^{- 0.02 t + c_{1}} + 20

Schritte zur Lösung

y^{'} (t) = - 0.02 (y - 20)

Solve separable ODE:

y = e^{- 0.02 t + c_{1}} + 20

y = e^{- 0.02 t + c_{1}} + 20

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