derivative of (6x/(sqrt(x^2+2)))

解

\frac{d}{d x} (\frac{6 x}{x ^{2} + 2})

\frac{12}{( x ^{2} + 2 ) x ^{2} + 2}

解答ステップ

\frac{d}{d x} (\frac{6 x}{x ^{2} + 2})

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{x}{x ^{2} + 2})

商の法則を適用:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 6 \cdot \frac{\frac{d x}{d x} x ^{2} + 2 - \frac{d}{d x} ( x ^{2} + 2 ) x}{( x ^{2} + 2 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 2) = \frac{x}{x ^{2} + 2}

= 6 \cdot \frac{1 \cdot x ^{2} + 2 - \frac{x}{x ^{2} + 2} x}{( x ^{2} + 2 ) ^{2}}

簡素化

6 \cdot \frac{1 \cdot x ^{2} + 2 - \frac{x}{x ^{2} + 2} x}{( x ^{2} + 2 ) ^{2}} : \frac{12}{( x ^{2} + 2 ) x ^{2} + 2}

= \frac{12}{( x ^{2} + 2 ) x ^{2} + 2}