y^'-7y=e^x

Lösung

y^{^{'}} - 7 y = e^{x}

y = - \frac{e ^{x}}{6} + c_{1} e^{7 x}

Schritte zur Lösung

y^{'} (x) - 7 y = e^{x}

Solve linear ODE:

y = - \frac{e ^{x}}{6} + c_{1} e^{7 x}

y = - \frac{e ^{x}}{6} + c_{1} e^{7 x}

x \to 4 lim (\frac{- 2}{x ^{2} - 16})

\frac{\partial}{\partial x} (x e^{4 y} sin (4 z))

x \to 0 + lim (x - \frac{1}{x})

h \to 0 lim (\frac{e ^{ah} - 1}{h})

y^{^{'}} = 3 - cos (x)